$f(x)=4x^3-4x+1\\ F(x)=x^4-\frac{x^2}{2}+x\\ \int_{-2}^{2} f(x)=F(2)-F(-2) \implies\\ (2)^4-\frac{2^2}{2}+2)-((-2)^2-\frac{(-2)^2}{2}-2)= \\ 16-2+2-(16-2-2)=16-(16-4)=4$

I've done this a million times and I'm still getting 4 instead of 32. Are you sure you posted the coefficients?

6 0

2 years ago

Help me please , I’ll mark brainliest

dexar [7]

Answer:

42 feet squared

Step-by-step explanation:

6 0

2 years ago

solve this equation. Does the equation have one solution, no solution, or infinitely many solutions use the drop-down menus to e

Artist 52 [7]

Answer:

Step-by-step explanation:

8(3x - 6) = 6(4x + 8)

24x - 48 = 24x + 48

24x - 24x = 48 + 48

0 ≠ 96

this will have NO SOLUTIONS....because no matter what value u put in for x, they will never be equal.

3 0

2 years ago

Read 2 more answers

What is the value of x?

frez [133]

$\left\{\begin{array}{ccc}x+2y=4&\text{multiply both sides by 5}\\4x-5y=42&\text{multiply both sides by 2}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}5x+10y=20\\8x-10y=84\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad13x=104\qquad\text{divide both sides by 13}\\\\\boxed{x=8}\\\\Answer:\ \boxed{\boxed{x=8}}$

5 0

2 years ago