Answer:
c4+8c3+−3c2+−7c
Step-by-step explanation:
Let's simplify step-by-step.
−3c4−5c2−7c+4c4+8c3+2c2
=−3c4+−5c2+−7c+4c4+8c3+2c2
Combine Like Terms:
=−3c4+−5c2+−7c+4c4+8c3+2c2
=(−3c4+4c4)+(8c3)+(−5c2+2c2)+(−7c)
=c4+8c3+−3c2+−7c
Answer:
the answer is "AB"
Step-by-step explanation:
I plugged it into photomath
Answer:
t= 2.52 hours
Step-by-step explanation:
It is given that for first 30 km, the speed of bicyclist is v km/hour
time taken to cover first 30 km is given by
(
)
for next 17 km the speed of bicyclist is 2 km/hour greater than his original speed
so the speed to cover next 17 km = v+2
time taken to cover next 17 km is given by

now total time t spent by the bicyclist to cover entire trip is given by


now if v=18 , we have

now to add fractions we make the denominator same
Hence we will find the LCM of 18 and 20
LCM of 18 and 20 = 180
now we need to make both the denominator equal to 180


hours (approx)
Answer:
The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
Step-by-step explanation:
The average speed is given by the following equation:

From 10A.M. to noon.
You traveled at 50mph during 2 hours. So how long you traveled?



You traveled 100 miles.
What was your average speed over the time interval from 9 A.M. to noon
From 9 A.M. to 10 A.M, you did not travel.
From 10 P.M. to noon, 100 miles.
So 100 miles during 3 hours.

The average speed over the time interval from 9 A.M. to noon was of 33.33 mph.
8 x .75 x 1.50 = 9 that is your answer