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Misha Larkins [42]
4 years ago
14

When a crystal grows in unrestricted space, how does growth occur?

Computers and Technology
2 answers:
insens350 [35]4 years ago
5 0
Hihi!

The correct answer would be C. Crystal faces accumulate atoms! If you need anymore help be sure to ask!

I hope I helped!
-Loliarual
blondinia [14]4 years ago
4 0

Answer:

Option (C)

Explanation:

Crystals are usually defined as the solids that are comprised of a regular and repeatable orientation of atoms. These molecules present in the atoms are linked with one another, giving rise to the formation of crystals. This arrangement of molecules of atoms is commonly known as the unit cell. They maintain the same type of arrangement throughout the entire substance.

This is how the crystal faces are generated by interlinking atoms with one another and crystals grow.

Thus, the correct answer is option (C).

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Write a program that produces this output:
AveGali [126]

Answer:

void printC()  

{  

   int i, j;  

   for (i = 0; i < 4; i++) //i indicate row number. Here we have 5 rows

       {  

         printf("C"); //print C for every row  

         for (j = 0; j < 6; j++) //j indicate column number. Here we have 7 Rows

         {  

           if (i == 0 || i == 4) //For first and last row  

               printf("C"); //print 'CCCCCCC'

          else if (i = 1|| i= 3) //for Second forth row  

                printf("C        +      +"); //print 'C    +    +'

          else if (i = 2) For second row  

                printf("C       +++++"); //print 'C +++++'

           else

               continue; //to jump to next iteration

         }  

         printf("\n"); // print in next line

}  

}

4 0
3 years ago
Write a Java class called BankAccount (Parts of the code is given below), which has two private fields: name (String) and balanc
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Answer:

Here is the Bank Account class:

public class Bank Account {   //class definition

   private String name;  //private String type field to hold name

   private double balance;    // private double type field to hold balance

    public Bank Account(String name, double balance) {  // parameter constructor that takes

//this keyword is used to refer to the data members name and balance and to avoid confusion between name, balance private member fields and constructor arguments name, balance

 this.name = name;  

 this.balance = balance;  }    

   public void deposit(double amount) {   //method to deposit amount

               balance = balance + amount;     }    // adds the amount to the account causing the current balance to increase

   public void withdraw(double amount) {  //method to withdraw amount

 balance = balance - amount;   }   //subtracts the amount causing the current balance to decrease

    public String toString() {  // to display the name and current balance

              return name + " , $" + balance; }  } //returns the name and the current balance separated by a comma and dollar

Explanation:

The explanation is provided in the attached document due to some errors in uploading the answer.

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3 years ago
In order to consolidate your theoretical knowledge into technique and skills with practical and applicational value, you will us
Arisa [49]

Answer:

Check the explanation

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To run Lasso Regression you can re-use the glmnet() function, but with the alpha parameter set to 1.

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Best cross-validated lambda lambda_cv <- lasso_cv$lambda.min # Fit final model, get its sum of squared residuals and multiple R-squared model_cv <- glmnet(X, y, alpha = 1, lambda = lambda_cv, standardize = TRUE) y_hat_cv <- predict(model_cv, X) ssr_cv <- t(y - y_hat_cv) %*% (y - y_hat_cv) rsq_lasso_cv <- cor(y, y_hat_cv)^2 # See how increasing lambda shrinks the coefficients -------------------------- # Each line shows coefficients for one variables, for different lambdas. # The higher the lambda, the more the coefficients are shrinked towards zero. res <- glmnet(X, y, alpha = 1, lambda = lambdas_to_try, standardize = FALSE) plot(res, xvar = "lambda") legend("bottomright", lwd = 1, col = 1:6, legend = colnames(X), cex = .7)

Kindly check the Image below.

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3 years ago
If you hold down the alt key and click anywhere in your document what happens
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<span>The Alt key on a PC is utilised to change the capacity of other squeezed keys. It will go to any desired short cut in the computer that is being accessed. in short , one can use this to reach other functionality of a windows based computer easily. For example, if you were accessing documents and you want to skip to a different function from what you were doing on the desktop.</span>
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4 years ago
Determine and prove whether an argument in English is valid or invalid. About Prove whether each argument is valid or invalid. F
yawa3891 [41]

Answer:

Each understudy on the respect roll got an A.  

No understudy who got a confinement got an A.  

No understudy who got a confinement is on the respect roll.  

No understudy who got an A missed class.  

No understudy who got a confinement got an A.  

No understudy who got a confinement missed class  

Explanation:

M(x): x missed class  

An (x): x got an A.  

D(x): x got a confinement.  

¬∃x (A(x) ∧ M(x))  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ M(x))  

The conflict isn't considerable. Consider a class that includes a lone understudy named Frank. If M(Frank) = D(Frank) = T and A(Frank) = F, by then the hypotheses are overall evident and the end is counterfeit. Toward the day's end, Frank got a control, missed class, and didn't get an A.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope got a confinement.  

Penelope missed class.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a confinement.  

Each understudy who missed class got a confinement.  

Penelope is an understudy in the class.  

Penelope didn't miss class.  

Penelope didn't get imprisonment.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got imprisonment.  

Each understudy who missed class or got imprisonment didn't get an A.  

Penelope is an understudy in the class.  

Penelope got an A.  

Penelope didn't get repression.  

M(x): x missed class  

S(x): x is an understudy in the class.  

D(x): x got a repression.  

An (ax): x got an A.  

H(x): x is on the regard roll  

An (x): x got an A.  

D(x): x got a repression.  

∀x (H(x) → A(x)) a  

¬∃x (D(x) ∧ A(x))  

∴ ¬∃x (D(x) ∧ H(x))  

Real.  

1. ∀x (H(x) → A(x)) Hypothesis  

2. c is a self-self-assured element Element definition  

3. H(c) → A(c) Universal dispatch, 1, 2  

4. ¬∃x (D(x) ∧ A(x)) Hypothesis  

5. ∀x ¬(D(x) ∧ A(x)) De Morgan's law, 4  

6. ¬(D(c) ∧ A(c)) Universal dispatch, 2, 5  

7. ¬D(c) ∨ ¬A(c) De Morgan's law, 6  

8. ¬A(c) ∨ ¬D(c) Commutative law, 7  

9. ¬H(c) ∨ A(c) Conditional character, 3  

10. A(c) ∨ ¬H(c) Commutative law, 9  

11. ¬D(c) ∨ ¬H(c) Resolution, 8, 10  

12. ¬(D(c) ∧ H(c)) De Morgan's law, 11  

13. ∀x ¬(D(x) ∧ H(x)) Universal hypothesis, 2, 12  

14. ¬∃x (D(x) ∧ H(x)) De Morgan's law, 13  

4 0
3 years ago
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