A fair ordinary dice is thrown once. Select the probability of getting a 4 or a 5?

1 answer:

6 0

There are 6 numbers on a dice 1,2,3,4,5,6. If you want to get a 4 or a 5, that would be 2 numbers out of the total number of numbers There 6 numbers in total so the probability of getting a 4 or 5 is 2 out of 6 or 1 out of 3 or 1/3

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There are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom. The three candidates that rece

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Answer:

Step-by-step explanation:

Given that there are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom.

The three candidates that receive the highest number of votes become candidates for a runoff election.

i.e. 3 persons out of 8 to be selected for becoming candidates for a runoff election.

Since order does not matter we use combinations here

3 persons out of 8 can be done in 8C3 ways

= 56

no of 3-candidate combinations possible are 56

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suppose y varies directly with the square root of x and inversely with z. when x=4 and z=3, then y=10. find y if x=49 and z=3

lyudmila [28]

$\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------$

$\bf \begin{array}{llll}
\textit{y varies directly with}\\
\textit{the square root of x and inversely with z}
\end{array}\qquad y=\cfrac{k\sqrt{x}}{z}
\\\\\\
\textit{we also know that }
\begin{cases}
x=4\\
z=3\\
y=10
\end{cases}\implies 10=\cfrac{k\sqrt{4}}{3}\implies 30=k2
\\\\\\
\cfrac{30}{2}=k\implies 15=k\qquad \qquad \boxed{y=\cfrac{15\sqrt{x}}{z}}
\\\\\\
\textit{when x = 49 and z = 3, what is \underline{y}?}\qquad \qquad y=\cfrac{15\sqrt{49}}{3}$

$\bf y=\cfrac{15\cdot 7}{3}\implies y=\cfrac{15}{3}\cdot 7\implies y=5\cdot 7\implies y=35$

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4 years ago