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Sophie [7]
3 years ago
8

bottle a contains 4 ounces of water, which is 25% of the amount of water in bottle b. How much water is in bottle b?

Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0
Idk is I’m right but....25%x4=1 which is the same as 100%
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Harry is one third as old as his father. If his father is x 12 years old, how old is Harry? StartFraction x over 3 EndFraction 4
Mama L [17]

The age of the Harry in the terms of variable <em>x, </em>as the age of his father is (x+4) is represent with following equation.

\sqrt{3}x+4

<h3>How to write algebraic expression? </h3>

Algebraic expression are the expression which consist the variables, coefficients of variables and constants.

The algebraic expression are used represent the general problem in the mathematical way to solve them.

Harry is one third as old as his father and his father is x+12 years old.To find the age of Harry, we need to convert the given statement into the algebraic expression.

Suppose the age of the Harry is <em>a</em> years and the age of his father is<em> b</em> years. Now Harry is one third as old as his father, thus

a=\dfrac{1}{3}b

Let the above equation is equation one.

As the father of Harry is x+12 years old. Thus put the value of age of his father in the equation one as,

a=\dfrac{1}{3}(x+12)\\a=\sqrt{3}x+4

The age of the Harry in the terms of variable <em>x, </em>as the age of his father is (x+4) is represent with following equation.

\sqrt{3}x+4\sqrt{3}x+4

Learn more about the algebraic expression here;

brainly.com/question/2164351

7 0
2 years ago
I want to i want to i want to
Rudik [331]

Answer:

What do you mean?

Step-by-step explanation:

7 0
2 years ago
Plz help me out with this
nadya68 [22]

Given,

  • HK is the perpendicular bisector of GJ. So, <u>GK = KJ</u>.
  • GK = 2x + 10
  • KJ = 3x - 15

_______________

Find KJ .

_______________

First find the value of x

\sf \: GK \:  = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x =  - 15 - 10 \\ \sf - x =  - 25 \\  \sf \: -  >   \boxed{\bf \: x = 25}

Now, find the value of KJ.

\sf3x - 15 \\  \sf= 3(25) - 15 \\  \sf=7 5 - 15 \\     = \boxed{\bf \: 60}

-> The value of KJ is <u>6</u><u>0</u><u>.</u>

_______________

Hope it helps.

RainbowSalt2222

6 0
3 years ago
Read 2 more answers
How are average I.Q.s related to normal distributions?
Flauer [41]

In USA the average I.Q. is 98 while the top one average I.Q. country is Hong Kong.

But the I.Q. distribution is given by a polinomial graph, few people with extremely low I.Q. 40~70, a lot between 70~100, some between 100~120, few between 120~140 and extremely low 140+

8 0
3 years ago
Read 2 more answers
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
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