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Vinvika [58]
3 years ago
5

An inlet pipe on a swimming pool can be used to fill the pool in 38 hours. The drain pipe can be used to empty the pool in 40 ho

urs. If the pool is 14 filled and then the inlet pipe and drain pipe are opened, how long from that time will it take to fill the pool?
Answer
Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0

To solve this problem you must apply the proccedure shown below:

1. In a hour you have \frac{1}{38} of the pool filled and \frac{1}{40}.Taking \frac{1}{4} of the pool filled, you have the following expression:

\frac{1}{38}-\frac{1}{40}=\frac{1}{4}/t

2. Solve for t, as following:

t=\frac{760}{4}\\ t=190 hours

The answer is: 190 hours

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A bottle holds exactly 2/3 pint of liquid. How many 2/3-pint bottles can be filled from a 24-pint container
kifflom [539]

Answer:

36 number of 2/3-pint bottles can be filled from a 24-pint container

Step-by-step explanation:

Volume of the container is 24 pint

Volume of the bottle is 2/3 pint

Number of 2/3 pint bottles that can be filled from 24 pint container is

\frac{24}{\frac{2}{3} } \\= 24 * \frac{3}{2} \\= 12 * 3\\= 36

36 number of 2/3-pint bottles can be filled from a 24-pint container

6 0
2 years ago
Which algebraic expressions are polynomials? Check all that apply. PLEASE HELP
dexar [7]
Selections 2, 3, 5, 6 are polynomials.

1 and 4 are not. The coefficients don't have to be integers, but the powers of the variables need to be positive integers. In 1, you have x^-1. in 4, you have x^(1/2).
3 0
3 years ago
Graph the system of​ equations, and determine the solution.<br> x+4y=8
bekas [8.4K]

Answer:

12

Step-by-step explanation:

5 0
3 years ago
Variance is: Multiple Choice the average squared deviations about the mean of a distribution of values. an empirically testable
DENIUS [597]

Multiple choice answers are clearly defined as below for clarity:

A. the average squared deviations about the mean of a distribution of values.

B. an empirically testable statement that is an unproven supposition developed in order to explain certain phenomena.

C. the error made by rejecting the null hypothesis when it is true.

D. a statement that asserts the status quo; that is, any change from what has been thought to be true is due to random sampling order.

E. a statement that is the opposite of the null hypothesis

Answer:

A. The average squared deviations about the mean of a distribution of values.

Explanation:

A. the average squared deviations about the mean of a distribution of values. Correct

Standard deviation is how data is distributed around the mean. It is also the square root of the Variance. Therefore, the variance is the square of the standard deviation which is distributed around the mean.

B. an empirically testable statement that is an unproven supposition developed in order to explain certain phenomena. Incorrect

This is false as this is rather the definition for hypothesis.

C. the error made by rejecting the null hypothesis when it is true. Incorrect

This is false as this is the definition for the probability of committing a type I error

D. a statement that asserts the status quo; that is, any change from what has been thought to be true is due to random sampling order. Incorrect

This is false as this defines what a null hypothesis is.

E. a statement that is the opposite of the null hypothesis. Incorrect

The opposite of the null hypothesis is alternative hypothesis.

6 0
2 years ago
The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either
kompoz [17]

The Rome data center is best described by the mean. The New York data center is best described by the median. The third option C is correct.

<h3>The Mean and Median:</h3>

The mean of a data set is the average of all the terms in the data set. The median of a data set is the value of the midpoint term in the frequency distribution.

From the given information, the table can be better expressed as:

           High   Low   Q1     Q3    IQR   Median    Mean         σ

Rome   18         1        3       7        4         6.5        6.4           4.3

NY        14         1       4.5    8.5      4        5.5        6.1            3.2

  • From the data sets in the table, the distribution for Rome is not largely diverse, and there isn't much departure from the mean value. It indicates that in the data set of Rome families, no outliers have occurred.

  • In New York, the data indicate a distinct outlier for New York families in Q3. This is due to the fact that the gap is so large, the mean may not be a good choice for determining the measure of the central tendency.

Therefore, we can conclude that, the Rome data center is best described by the mean and the median will be utilized to determine the central tendency in New York.

Learn more about mean and median here:

brainly.com/question/14532771

4 0
2 years ago
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