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3 years ago

13

Sketch 8 points that are verticies of a closed plane figure connect the points to draw the figure.

1 answer:

exis [7]3 years ago

8 0

An octogon is an eight sided and eight cornered shape

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The price of a game that's been discounted<br> 18% off its list price (x)

Dmitry_Shevchenko [17]

Answer:

The price of a game is $0.82x$

Step-by-step explanation:

Let

x ----> the list price of a game

Remember that

$100\%-18\%=82\%=82/100=0.82$

To find out the price of a game that's been discounted 18% off its list price, multiply the list price by the number 0.82

so

$(x)(0.82)=0.82x$

7 0

3 years ago

Why is the function below (the picture above) not a linear function?

satela [25.4K]

For function to be linear , degree(highest power must be 1) like y=2x but here....y=constant which has a degree 0 hence not linear

3 0

3 years ago

Solve -1.5x+6=15 for x

sp2606 [1]

Answer:

<h2>x = -6</h2>

Step-by-step explanation:

$-1.5x+6=15\qquad\text{suntract 6 from both sides}\\\\-1.5x+6-6=15-6\\\\-1.5x=9\qquad\text{divide both sides by (-1.5)}\\\\\dfrac{-1.5x}{-1.5}=\dfrac{9}{-1.5}\\\\x=-6$

6 0

3 years ago

Determine the coordinates of the vertices of the triangle to compute the area of the triangle using the distance formula (round

Karo-lina-s [1.5K]

Answer:

1. D. $50\text{ units}^2$

2. D. 45 units.

Step-by-step explanation:

We have been two graphs.

1. To find the area of our given triangle we will use distance formula.

$\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Upon substituting coordinates of base line of our triangle we will get,

$\text{Base length of triangle}=\sqrt{(15-5)^2+(5-15)^2}$

$\text{Base length of triangle}=\sqrt{(10)^2+(-10)^2}$

$\text{Base length of triangle}=\sqrt{100+100}$

$\text{Base length of triangle}=\sqrt{200}$

$\text{Base length of triangle}=10\sqrt{2}$

Now let us find the height of triangle similarly.

$\text{Height of triangle}=\sqrt{(20-15)^2+(10-5)^2}$

$\text{Height of triangle}=\sqrt{(5)^2+(5)^2}$

$\text{Height of triangle}=\sqrt{25+25}$

$\text{Height of triangle}=\sqrt{50}$

$\text{Height of triangle}=5\sqrt{2}$

$\text{Area of triangle}=\frac{\text{Base*Height}}{2}$

$\text{Area of triangle}=\frac{10\sqrt{2}*5\sqrt{2}}{2}$

$\text{Area of triangle}=\frac{50*2}{2}$

$\text{Area of triangle}=50$

Therefore, area of our given triangle is 50 square units and option D is the correct choice.

2. Using distance formula we will find the length of large side of triangle as:

$\text{Large side of rectangle}=\sqrt{(14-1)^2+(21-8)^2}$

$\text{Large side of rectangle}=\sqrt{(13)^2+(13)^2}$

$\text{Large side of rectangle}=\sqrt{169+169}$

$\text{Large side of rectangle}=\sqrt{338}$

$\text{Large side of rectangle}=13\sqrt{2}$

$\text{Small side of rectangle}=\sqrt{(4-1)^2+(5-8)^2}$

$\text{Small side of rectangle}=\sqrt{(3)^2+(-3)^2}$

$\text{Small side of rectangle}=\sqrt{9+9}$

$\text{Small side of rectangle}=\sqrt{18}$

$\text{Small side of rectangle}=3\sqrt{2}$

$\text{Perimeter of rectangle}=2(\text{Length + Width)}$

$\text{Perimeter of rectangle}=2(13\sqrt{2}+3\sqrt{2}}$

$\text{Perimeter of rectangle}=2(16\sqrt{2}}$

$\text{Perimeter of rectangle}=32\sqrt{2}$

$\text{Perimeter of rectangle}=45.2548339959390416\approx 45$

Therefore, the perimeter of our given rectangle is 45 units and option D is the correct choice.

8 0

4 years ago

Read 2 more answers

PLEASE HELP! I really need to know this asap! Thank you! Brainliest answer

kupik [55]

Answer:

its should be 1 or 3 because 224 makes no solense go by what ur mind tells u

6 0

3 years ago