Solve the equation for the unknown variable z3=-64
2 answers:
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(a) It looks like you're saying
Find the critical points of F(x). By the fundamental theorem of calculus,
F'(x) = x - 3x² + 7
The critical points are where the derivative vanishes. Using the quadratic formula,
x - 3x² + 7 = 0 ⇒ x = (1 ± √85)/6
Compute the second derivative of F :
F''(x) = 1 - 6x
Check the sign of the second derivative at each critical point.
• x = (1 + √85)/6 ≈ 1.703 ⇒ F''(x) < 0
• x = (1 - √85)/6 ≈ -1.370 ⇒ F''(x) > 0
This tells us F attains a minimum of
(b) Split up the domain of F at the critical points, and check the sign of F'(x) over each subinterval.
• over (-∞, -1.370), consider x = -2; then F'(x) = -7 < 0
• over (-1.370, 1.703), consider x = 0; then F'(x) = 7 > 0
• over (1.703, ∞), consider x = 2; then F'(x) = -3 < 0
This tells us that
• F(x) is increasing over ((1 - √85)/6, (1 + √85)/6)
• F(x) is decreasing over (-∞, (1 - √85)/6) and ((1 + √85)/6, ∞)
(c) Solve F''(x) = 0 to find the possible inflection points of F(x) :
F''(x) = 1 - 6x = 0 ⇒ 6x = 1 ⇒ x = 1/6
Split up the domain at the inflection point and check the sign of F''(x) over each subinterval.
• over (-∞, 1/6), consider x = 0; then F''(x) = 1 > 0
• over (1/6, ∞), consider x = 2; then F''(x) = -11 < 0
This tells us that
• F(x) is concave up over (-∞, 1/6)
• F(x) is concave down over (1/6, ∞)
Hi, I'm Jenny from ExperimentsDIYS and I'm here to help you with your math! :)
I am assuming that you need help with question #1 so we will proceed with that one.
Lets first divide 1,875 ÷ 9.
Using a calculator, this is equal to 208.333333333
We can simplify this number by rounding up.
208.33 would be your answer rounded.
The first digit in this quotient ( Which is the answer to a division problem) is using place value.
The decimal place value chart is attached.
The first digit will be in the hundreds place because it is on the left side of the decimal point.
We are ecstatic to help and if there are any more problems or if we got any answers wrong please tell us! Thank you <3
-ExperimentsDIYS
