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Scilla [17]
3 years ago
11

How do you know which bacteria is growing faster?

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:when the cells seem to be moving faster and multiply at a smaller rate of speed

Step-by-step explanation:

also thats just science

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Jeff earns $27,800 per year. what is his bi-monthly gross pay
Anarel [89]
Below are the choices that can be found elsewhere:

<span>a. $1,158.33
b. $1,069.23
c. $2,316.66
d. $1,539.22
</span>
Below is the solution:
$27,800 / 12 months = 2,316
$2,316 / 2 since it bi-monthly = $1,158.33

Thank you for posting your question here. I hope the answer helps. 

3 0
3 years ago
Solve for X. Plz I can't figure it outtt!
WINSTONCH [101]

9514 1404 393

Answer:

  x = 40

Step-by-step explanation:

The angle bisector divides corresponding sides proportionally.

  x/16 = 25/10

  x = 16(25/10) . . . . . multiply by 16

  x = 40

7 0
2 years ago
Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
maks197457 [2]
F(g(x)) = [(-7x-8)/(x-1) - 8} / [(-7x - 8)/(x-1) + 7] =

[(-7x - 8 - 8(x-1)) / (x-1)] / [(-7x - 8 + 7(x-1)) / (x-1)] = (-15x) / (-15) = x.

g(f(x)) = [-7*(x-8)/(x+7) - 8] / [(x-8)/(x+7) - 1] =

[(-7x + 56 -8*(x+7)) / (x+7)] / [(x - 8 - (x + 7)) / (x+7)] = (-15x) / (-15) = x.

So since f(g(x)) = g(f(x)) = x we can conclude that f and g are inverses.
5 0
2 years ago
The table shows the number of diagonals that can be drawn from one vertex in polygon. Write an equation in function notation for
Reil [10]

Answer:

y = x - 3; 9 diagonals

Step-by-step explanation:

Find the equation: y = x - 3

Plug in 12: y = 12 -3

Solve: y = 9

9 diagonals

Hope this helps! Plz mark brainliest

3 0
2 years ago
When data is displayed with a scatter plot, it is often useful to attempt to represent that data with the equation of a straight
Alexus [3.1K]
The line is often referred to as the "line of best fit", this line is drawn so that more accurate conclusions can be drawn from given data. This has numerous uses across the sciences.
4 0
2 years ago
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