Answer:
Step-by-step explanation:
because y² + 4y + 5 = (y+2)² + 1 > 0, ∀ y ∈ R
=> y² + 4y + 5 = 0 is unreasonable
=> no solutions
N-3n=14-4n
N-3n+4n=14
2n=14
N=14÷2
N = 7 To check substitute 7-3(7)=14-4(7)
7-21=14-28
-14=-14
This expression has four terms.
5, 9x, 7, and 2x
A term is a constant number, a variable, or a variable with a coefficient.
Answer:
Step-by-step explanation:
Given that the 2 triangles are congruent based on the Hypotenuse-leg theorem, this implies that:
, and 
Using the expression, , solve for y:
The correct graph is graph 4.
You can find this by looking for recognizable points. This is the easiest way to find composite graphs. In the graph f(x) =|x − 5| + |x − 4| both 5 and 4 yield the answer of 1. You can see that in the examples below:
<span>f(x) =|x − 5| + |x − 4|
</span><span>f(5) =|5 − 5| + |5 − 4|
</span><span>f(5) =|0| + |1|
f(5) = 0 + 1
f(5) = 1
</span><span>f(x) =|x − 5| + |x − 4|
</span><span>f(4) =|4 − 5| + |4 − 4|
</span><span>f(4) =|-1| + |0|
f(4) = 1 + 0
f(4) = 1
Now we can look for graphs that have those two reference points. The 4th graph is the only one that has those. </span>
