<span>false
In the United States, the cases most regularly connected with liability as it relates to product are carelessness, strict obligation, rupture of guarantee, and different buyer insurance claims. The lion's share of item risk laws are resolved at the state level and shift generally from state to state.</span>
<u>Answer:</u>
<em>The </em><em>executives programming enables associations</em><em> to set up representative execution guidelines and empowers chiefs to assess a worker's activity execution in </em><em>connection to these measures.</em>
<u>Explanation:</u>
Organizations use execution the <em>board programming to encourage important </em>and progressing exchanges among chiefs and direct reports.
The executives programming is most regularly actualized by <em>HR offices to help chief level staff </em>all through different offices assess representatives, direct worker execution surveys, keep up a record of dialog points, and encourage <em>360-degree criticism.</em>
Answer:
$14038
Explanation:
The company has marginal revenue R'(t) = 
. Therefore its revenue R(t) is given as;
R(t) = ∫R'(t)
R(t)= ∫ dt = + c
R(t) = + c
But R(0) = 0, therefore:
R(0) = 
+ c = 0
+ c = 0
100 + c =0
c = -100
Also the marginal cost per day is given by C'(t) = 140 - 0.3t
C'(t) = 140 - 0.3t
C(t) = ∫C(t) = ∫ (140 - 0.3t) dt = 140t - (0.3/2) t² + C
But C(0) = 0
C(0) = 140 (0) - (0.3/2)(0)² + c = 0
c = 0
C(0) = 140t - (0.3/2) t²
Profit P(t) = R(T) - C(T) , hence the total profit from t = 0 to t = 5 is given as:
P(t) = ![\int\limits^0_5 {[R'(t)-C'(t)]} \, dt =\int\limits^0_5 {([100e^t-(140-0.3t)]} \, dt=\int\limits^0_5 {100e^t} \, dt +\int\limits^0_5 {-0.3t} \, dt +\int\limits^0_5 {-140} \, dt \\\\=[100e^t]_0^5+[ -140t]_0^5+[-0.3t^2/2]_0^5=[14841.316-100]+[-700]+[-3.75]=14038](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_5%20%7B%5BR%27%28t%29-C%27%28t%29%5D%7D%20%5C%2C%20dt%20%3D%5Cint%5Climits%5E0_5%20%7B%28%5B100e%5Et-%28140-0.3t%29%5D%7D%20%5C%2C%20dt%3D%5Cint%5Climits%5E0_5%20%7B100e%5Et%7D%20%5C%2C%20dt%20%20%2B%5Cint%5Climits%5E0_5%20%7B-0.3t%7D%20%5C%2C%20dt%20%20%2B%5Cint%5Climits%5E0_5%20%7B-140%7D%20%5C%2C%20dt%20%20%5C%5C%5C%5C%3D%5B100e%5Et%5D_0%5E5%2B%5B%20-140t%5D_0%5E5%2B%5B-0.3t%5E2%2F2%5D_0%5E5%3D%5B14841.316-100%5D%2B%5B-700%5D%2B%5B-3.75%5D%3D14038)
The profit is $14038
Answer:
c. Optimum replacement interval (ORI)
Explanation:
Optimum replacement interval used to estimate the most cost effective time to replace an asset on the basis of their replacement cost.
There needs to be a balance between the replacement cost and the value that is being lost by changing the asset.
The useful value must be low to justify replacement cost.
For example if the cost of maintaining a machine has increased a lot as a result of wear and tear, it will be more cost effective to make a replacement in order to minimise cost and increase efficiency
I believe the answer is: Enable phase
During the enable phase, a company would evaluate the progess and determine additional planing necessary to ensure that the operation run smoothly. Often times, transferring responsibilities to another organization that had larger jurisdiction would be seen as a more appropriate decision.
