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3 years ago

What is the solution to the system of equations represented by the two equations?

2 answers:

6 0

There are 2 placeholder
it's easier if we had one
get rid of one with subsitutuion
y=-2x+7
y=1/3x
therefor
-2x+7=y=1/3x
-2x+7=1/3x
solve for x
multipl yboth sides by 3
-6x+21=x
add 6x to both sides
21=7x
divide both sides by 7
3=x
subsitute
y=1/3x
y=1/3(3)
y=3/3
y=1

the solution is x=3
y=1 or the point
(x,y)
(3,1)

Iteru [2.4K]3 years ago

5 0

If you would like to solve the following system of equations, you can do this like this:

y = - 2 * x + 7
y = 1/3 * x
____________
1/3 * x = - 2 * x + 7
1/3 * x + 2 * x = 7
1/3 * x + 6/3 * x = 7
7/3 * x = 7 /*3/7
x = 7 * 3 / 7
x = 3

y = 1/3 * x = 1/3 * 3 = 1

The correct result would be: x = 3 and y = 1.

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What is the Cost Price?<br><br> Cost price: $60 and Loss: 12 1/2%

bekas [8.4K]

Answer, 60 and Loss =12½. The selling price or the S.P. is Rs. 45.:

Step-by-step explanation:

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2 years ago

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An ice cream machine produced 52 ice creams per minute. After reconditioning, its speed increased to 65 ice creams per minute. B

Anastasy [175]

Answer:25 %

Step-by-step explanation:

Given

Earlier machine was producing 52 ice cream per minute and

Now it is Producing 65 ice creams per minute

So percentage increase of the machine $=\frac{\text{final-Initial}}{\text{Initial}}\times 100$

$=\frac{65-52}{52}\times 100$

$=\frac{13}{52}\times 100$

$=\frac{1}{4}\times 100=25\ \%$

So there is increase of 25 % in speed

5 0

3 years ago

The population of a town grows at a rate proportional to the population present at time t. The initial population of 500 increas

olga_2 [115]

Answer:

The population would be 781.

The population is growing with the rate of 12.50 persons/yr.

Step-by-step explanation:

Since, the formula for calculating the population, increasing with a rate per period,

$A=P(1+r)^{n}$

Where, P is the initial population,

r is the rate per period,

n is the number of period,

t is the total years,

Here, P = 500, r = 25 % = 0.25, n = 2 ( the number of '10 year period' of in 20 years is 2 )

Hence, the population in 20 years would be,

$A=500(1+0.25)^2=500(1.25)^2=781.25\approx 781$

Now, the rate of increasing per 10 year is 25 %,

⇒ The rate of increasing per year is 2.5 %,

Thus, the growing people per year = 2.5 % of 500 = 0.025 × 500 = 12.50

Hence, the population is growing at 12.50 person per year.

4 0

3 years ago

If peter can type 80 words in 2 minutes how many words can he type in 5 minutes if he continues to type at the same rate. Show a

klasskru [66]

Answer:

200 words are peter can be type in 5 minutes.

Step-by-step explanation:

As given

If peter can type 80 words in 2 minutes .

i.e

80 words = 2 minutes

Now words type in 1 minutes.

$1\ minutes = \frac{80}{2}\ words$

1 minutes = 40 words

Now calculate number of words are type in 5 minutes.

Words are type in 5 minutes = Number of minutes × Number of words are type in 1 minutes.

Number of minutes = 5 minutes

Number of words are type in 1 minutes = 40 words

Words are type in 5 minutes = 5 × 40

= 200 words

Therefore 200 words are peter can be type in 5 minutes.

4 0

4 years ago

Katie is building a rectangular wall. The wall will be 332 bricks wide and 39 bricks tall. She has 15,000 bricks. Does she have

agasfer [191]

Katie has enough bricks because it only takes 12,948 bricks to build the wall. To get 12,948, you will multiply 332 by 39. So basically you are multiplying the width by how tall it is.

4 0

4 years ago

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