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sammy [17]
3 years ago
8

What is the solution to the system of equations represented by the two equations?

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0
There are 2 placeholder
it's easier if we had one
get rid of one with subsitutuion
y=-2x+7
y=1/3x
therefor
-2x+7=y=1/3x
-2x+7=1/3x
solve for x
multipl yboth sides by 3
-6x+21=x
add 6x to both sides
21=7x
divide both sides by 7
3=x
subsitute
y=1/3x
y=1/3(3)
y=3/3
y=1

the solution is x=3
y=1 or the point
(x,y)
(3,1)
Iteru [2.4K]3 years ago
5 0
If you would like to solve the following system of equations, you can do this like this:

y = - 2 * x + 7
y = 1/3 * x
____________
1/3 * x = - 2 * x + 7
1/3 * x + 2 * x = 7
1/3 * x + 6/3 * x = 7
7/3 * x = 7      /*3/7
x = 7 * 3 / 7
x = 3

y = 1/3 * x = 1/3 * 3 = 1

The correct result would be: x = 3 and y = 1.
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Step-by-step explanation:

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a) Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

a) Nota - Puesto que la ecuación que describe el Coste ya existe en el enunciado, entonces se entiende el verbo <em>"Expresa"</em> como <em>"Describa en sus propias palabras"</em>.

Como puede apreciarse el Coste de la línea telefónica móvil aumenta linealmente con el Tiempo de consumo por parte del usuario. En consecuencia, la función de Coste queda definida como sigue:

C(t) = C_{o} + r\cdot t (1)

Donde:

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  • r - Tasa de consumo, en soles por hora.

Entonces, tenemos que Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

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c) Si sabemos que C_{o} = 10, r = 1,5 y t = 48, entonces el Coste Total por concepto de 48 horas de consumo es:

C(48) = 10 + 1,5\cdot (48)

C(48) = 82

El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

Invitamos a ver este problema sobre Costes: brainly.com/question/15723794

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Answer:

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18 divided by 4 is 4.5

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