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Kazeer [188]
3 years ago
15

Which expression is not a perfect square trinomial?

Mathematics
2 answers:
puteri [66]3 years ago
8 0

Answer:

Remember that a perfect square trinomial can be factored into the form (a+b)^2

or (a-b)^2

Examples:

(x+2)(x+2) is a perfect sq trinomial --> x^2+4x+4

(x-3)(x-3) is a perfect sq trinomial --> x^2-6x+9

(x+2)(x-3) is not a perfect square trinomial because its not in the form (a+b)^2 or (a-b)^2

Now to answer your question,

for the first one, x^2-16x-64, you cannot factor it so it is not a perfect square trinomial

for the second one, 4x^2 + 12x + 9, you can factor that into (2x+3)(2x+3) = (2x+3)^2 so this is a perfect square trinomial

for the third one, x^2+20x+100 can be factored into (x+10)(x+10) so this is also a perfect square trinomial

for the fourth one, x^2+4x+16 cannot be factored so this is not a perfect square trinomial

Therefore, your answer is choices 2 and 3

Read more on Brainly.com - brainly.com/question/10522355#readmore

Step-by-step explanation:

belka [17]3 years ago
8 0

Answer:

A. 121 plus 11 y plus y squared; 121+11y+y^2

Step-by-step explanation:

We are asked to choose the expression that is not a perfect square trinomial.

We know that a perfect square trinomial is in form a^2\pm 2ab+b^2.

A. 121 plus 11 y plus y squared

121+11y+y^2

11^2+11y+y^2

For this expression to be a perfect square trianomal, the middle term needs to be 2*11y=22y. Since the middle term is not equal to 2ab, therefore, option A is not a perfect square trinomial.

B. 100 minus 20 y plus y squared

100-20y+y^2

10^2+2*10y+y^2

Therefore, option B is a perfect square trinomial.

C. 81 plus 18 y plus y squared

81+18y+y^2

9^2+2*9y+y^2

Therefore, option C is a perfect square trinomial.

D. 144 plus 24 y plus y squared

144+24y+y^2

12^2+2*12y+y^2

Therefore, option D is a perfect square trinomial.

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What is an equation of the line that passes through the point (-7, -6) and is parallel to the line x-y=7?
Alex_Xolod [135]

Answer:

Step-by-step explanation:

For two lines to be parallel their slopes must be equal. For two lines to be perpendicular their slopes must be the negative reciprocal of each other.

Step 1 Find the slope of the equation.

Put it into the slope-intercept form. y = mx + b.  

For x-y = 7, move the x to the left; therefore subtract the x from both sides. this leaves you  -y = -x + 7

Then, divide both sides by -1 to get a positive y.  -y/-1 = (-x + 7)/-1

This leaves y = x - 7  The slope(m) for this equation is m = 1

The other equation must also have a slope of 1 or m=1 for the lines to be parallel.

Use the point given to you (-7, -6) and substitute for (x, y)

The slope-intercept form y = mx + b can once again be used.

x = -7, y =-6, and slope or m = 1

Therefore,  y = mx + b substituted will be -6 = (1)(-7) + b; now, solve for b which is the y intercept

-6 = -7 + b add 7 to both sides -6 +7 = -7 + b +7 ; therefore, b = 1

Now you know the slope(m) which is equal to 1 and the y-intercept(b) which is equal to 1.

Finally, substitute the m and b in the slope-intercept form

            y = (1)x + 1 or y = x +1

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