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3 years ago

The volume of a sphere with a 10-in. radius is

Mathematics

2 answers:

jenyasd209 [6]3 years ago

3 0

V = 4/3 * (pi) * r^3
V = 4/3 * (pi) * 10^3
V = 4/3 * (pi) * 1000
V = 4000/3(pi)
V = 1333 1/3 (pi) in^3 <==

olga55 [171]3 years ago

3 0

volume of a sphere = 4/3 * PI *r^3

v = 4/3*PI *10^3

v = 4/3*PI*1000

v = 1333 1/3PI in^3

Answer is B

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The Li family is going hiking. The distance from their car can be found using the function d(t) = 3t + 1, where d is the miles a

Sauron [17]

Answer:

Step-by-step explanation:

d(t)=3t+1 but d(t)=7

distance*time=3*time+1

so d(t)=7 is the same as

d(t)=3(2)+1

meaning that you hiked for 2 hours.

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3 years ago

The radius of a size 5 soccer ball is approximately 11.5 cm. How many square inches of synthetic leather does it

kakasveta [241]

Answer:

1661.06 cm²

Step-by-step explanation:

From the question given above, the following data were obtained:

Radius (r) = 11.5 cm

Size of synthetic leather needed =?

To know how many square centimetres of synthetic leather needed to cover the ball, we shall determine the area of the ball. This can be obtained as follow:

Radius (r) = 11.5 cm

Pi (π) = 3.14

Area of ball =?

The shape of a ball is spherical in nature. Thus, we shall apply the formula for calculating the area of a sphere. This is illustrated below:

A = 4πr²

A = 4 × 3.14 × 11.5²

A = 4× 3.14 × 132.25

A = 1661.06 cm²

Thus, 1661.06 cm² of synthetic leather needed to cover the ball.

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3 years ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$