Use tiles to find all the factors of the product. Record the arrays on grid paper and write the factors shown.

Mathematics

1 answer:

ahrayia [7]3 years ago

6 0

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? A mug can hold 13.46 oz of coffee without overflowing. The radius of the mug is 3 cm. Given that 1 cm3 equals 0.034 oz, what i

Elan Coil [88]

Answer:

14 cm

Step-by-step explanation:

Given:

A mug can hold 13.46 oz of coffee.

The radius of the mug is 3 cm.

Given that 1 $cm^{3}$ equals 0.034 oz.

Question asked:

What is the height of the mug to the nearest centimeter ?

Solution:

Given that 1 $cm^{3}$ equals 0.034 oz.

By unitary method:

0.034 oz = 1 $cm^{3}$

1 oz = $\frac{1}{0.034}$

13.46 oz = $\frac{1}{0.034}\times13.46 =395.88 \ cm^{3}$

A mug can hold 13.46 oz of coffee means volume of cylinder is given which is 395.88 $cm^{3}$ . Now we can find the height of the mug by using volume of cylinder formula:

volume of cylinder = $\pi r^{2} h$

$395.88=\frac{22}{7} \times3\times3\times \ h\\395.88=\frac{198 \ h}{7}$

By cross multiplication:

$395.88\times 7 =198\ h\\2771.16= 198\ h$

By dividing both side by 198

$h = 13.99$ $cm$

Therefore, height of the mug to the nearest centimeter is 14 cm.

6 0

3 years ago

Read 2 more answers

Which of the following is an asymptote of y = sec(x)?

babunello [35]

Answer: option d. x = 3π/2

Solution:

function y = sec(x)

1) y = 1 / cos(x)

2) When cos(x) = 0, 1 / cos(x) is not defined

3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...

4) limit of sec(x) = lim of 1 / cos(x).

When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.

So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).

Answer: 3π/2

The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).