Answer:
There are 60 permutations that can be formed from the first five letters of the alphabet.
Step-by-step explanation:
The number of three letter permutations that can be formed from the first five letters of the alphabet is 
.
= 60
Hence, there are 60 permutations that can be formed from the first five letters of the alphabet.
There are certain rules to follow when rotating a point 90 deg clockwise. Since it is given that ABCD is a parallelogram and the coordinates of point C are given, we just have to follow this simple relation:
R(90 deg) : (X,Y) ---> (-Y,X)
Using the given coordinates:
R(90 deg<span>) : (-4,1) ---> (-1,-4)
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Therefore, Point C' will be located at (-1,-4)
Subtract the second equation from the first equation.
x = -1
Plug -1 back in to either equation and solve for y.
3(-1) + y =-10
-3 + y = -10
Add 3 to both sides
y = -7
CHECK
3(-1) -7 = -10
2(-1) -7 = -9
(-1, -7)
Answer:
56
Step-by-step explanation:
clearly, the sequence is built by adding 5 for every new term.
so, an = an-1 + 5
a1 = 25 (the starting value)
a2 = a1 + 5 = 25 + 5 = 30
a3 = a2 + 5 = a1 + 5 + 5 = a1 + 2×5 = 25 + 10 = 35
...
an = an-1 + 5 = a1 + (n-1)×5
now, we know, the last term is 300.
when we determine for which n we get an = 300, we know that n is the number of terms in the sequence.
so,
300 = a1 + (n-1)×5 = 25 + 5n - 5 = 20 + 5n
280 = 5n
n = 56
a56 = 300
so, we have 56 terms in this sequence
Answer:
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