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Lera25 [3.4K]
3 years ago
5

What are binary numbers

Mathematics
2 answers:
Yakvenalex [24]3 years ago
7 0
Represents the numeric values using 2 different symbols

Hope it helped!
Vanyuwa [196]3 years ago
3 0
Binary numbers are numbers expressed in the binary numeral system or base -2 which represents numeric values using 2 different symbols.
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PLZ ANSWER URGENT<br> A).1+ 4x+2/2x=5x<br> b).2x-2+3x/4=2x
Elena L [17]

A.

Divide the numbers

1 + 4x 2/2 • x =5x

1 + 4x + 1x =5x

Multiply by 1

1 + 4x + 1x=5x

Combine like terms

1 + 4x + x =5x

1 + 5x =5x

Subtract 1 from both sides of the equation

5x + 1 = 5x

5x + 1 - 1 =5x -1

Simplify

Subtract the numbers

5x = 5x -1

Subtract 5x from both sides of the equation

5x = 5x -1

5x - 5x = 5x -1 -5x

Simplify

0= -1

Result

0= -1

idk the ans in letter B

5 0
4 years ago
Please can I check with you the answer for nbr 12?<br> Is it correct?
Crank

Answer:

B and C

Step-by-step explanation:

  • B = 2,4,6
  • =3,6
  • C= 2,4,6,8,10,12
  • = 6,12
8 0
2 years ago
I need help with this problem
natulia [17]
There are 3 shorter boards because if you divide 27 by 9 it equals 3. 
3 0
4 years ago
Read 2 more answers
5. Jose figures the prom will cost
mars1129 [50]

Answer:

Step-by-step explanation:

19 hours

7 0
3 years ago
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A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. A random sample of 28 rounds of golf
Ratling [72]

Answer:

Step-by-step explanation:

Hello!

Interest hypothesizes is that the variance of the golfer's scores equals to δ²= 10.0.

A random sample of 28 rounds of golf had a sample standard deviation S= 3.5

The statistics hypotheses are:

H₀: δ²= 10.0

H₁: δ²≠ 10.0

α: 0.05

To conduct a hypothesis test for the population variance you have to work using the Chi-Square distribution, this test is two-tailed so you will have two critical values. Between these two values is defined as the "not rejection region" and below and above them lies the "rejection region"

Lower critical value: X^2_{n-1; \alpha /2}= X^2_{27; 0.05}= 16.928

Upper critical value: X^2_{n-1;1-\alpha /2}= X^2_{27;0.95}= 40.113

If X^2_{H_0} ≤ 16.928 or X^2_{H_0} ≥ 40.113, the decision is to reject the null hypothesis.

If 16.928 < X^2_{H_0} < 40.113, the decision is to not reject the null hypothesis.

X^2= \frac{(n-1)S^2}{Sigma^2} ~~X^2_{n-1}

X^2_{H_0}= \frac{(28-1)12.25}{10} = 33.075

The calculated X^2_{H_0} is between the two critical values, so the decision is to not reject the null hypothesis. We can conclude that the population variance fro this golfers play score is 10.

I hope this helps!

5 0
3 years ago
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