So if John gives a pen and pencil to each and all of them are over we know that the no. of pencils and pens should be the same
So we will find the LCM of 15 and 40 that is equal to 120
So John brought 120/15 that is 8 packets of pen and 120/40 that is three packets of pencils
Answer:
h(d) = (17/3249)(-d² +114d)
Step-by-step explanation:
For this purpose, it is convenient to translate and scale a quadratic parent function so it has the desired characteristics. We can start with the function ...
f(x) = 1 -x² . . . . . . . has zeros at x = ±1 and a vertex at (0, 1)
We want to horizontally expand this function by a factor of 57, so we can replace x by x/57. We want to vertically scale it by a factor of 17, so the vertex is at (0, 17). Finally, we want to translate the function 57 m to the right, which requires replacing x with x-57. After these transformations, we have ...
f(x) = 17(1 -((x-57)/57)²) = (17/3249)(-x²+114x)
Using the appropriate function name and variable, we have ...
h(d) = (17/3249)(-d² +114d)
Answer: x = 780
Step-by-step explanation: Well <u><em>percent</em></u> means <em>over 100</em> so we can set up an equation for this problem by reading it from left to right.
So we know that <u><em>10%</em></u> means <em>10/100</em>, <u><em>of</em></u> means times, <em><u>what</u></em> <em><u>number</u></em> means <em>x</em>, <u><em>is</em></u> means <em>equals</em>, and <em><u>12</u></em> means 12.
Notice that <em>10/100</em> can be reduced to 1/10.
So rewriting our problem we have <em>X/10 = 78</em>.
To get rid of the fraction, we multiply both sides of the equation by 10 and we have <em>x = 780</em>. So, 10% of 780 is 78.
Now let's check our answer back in the original problem to see if it makes sense.
We have <em>10% of 780 is 78</em>. Well we know that 100% of of 780 would be 780 so 10% of 780 should be alot less than 780 so 78 seems to make sense.
Image provided showing my work.
Answer:
a n y a n s w e r
Step-by-step explanation: