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ra1l [238]
3 years ago
14

Need help ratio table

Mathematics
1 answer:
liberstina [14]3 years ago
7 0

Answer:6

Step-by-step explanation:

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Simplify the expression 7(1 +5v) =​
horsena [70]
The answer is 7 + 35v
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3 years ago
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The length of the rectangle is 7/(x-4) feet, while its width is 5/x feet. Find its perimeter. Please help asap!!!!! :(
damaskus [11]

The perimeter would be (24x - 40)/(x^2 - 4x).

In order to find this, first double the length and width as you would to find any perimeter.

7/(x - 4) * 2 = 14/(x - 4)

5/x * 2 = 10/x

Now to add those together, we need to give them common denominators. In order to do that with the first one, we need to multiply by x/x

14/(x - 14) * x/x = 14x/(x^2 - 14x)

Then we can do the same with the second part by multiplying by (x - 4)/(x - 4)

10/x * (x - 4)/(x - 4) = (10x - 40)/(x^2 - 14x)

Now we can add the two together

14x/(x^2 - 14x) + (10x - 40)/(x^2 - 14x) = (24x - 40)/(x^2 - 14x)

3 0
3 years ago
Yesterday, Janie walked 3
ch4aika [34]

Answer:

i will answer -- justv please clarify ur question

ig its 8.7 tho ?

Step-by-step explanation:

8 0
3 years ago
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write the standard form of the equation of the circle with the given center and radius (6,4), r= square root of 7
REY [17]

The standard form of the equation of a circle is (x-6)^{2}+(y-4)^{2}=7.

Solution:

Center of the circle = (6, 4)

Radius of the circle = \sqrt{7}

<u>To find the equation of the circle:</u>

General formula for the equation of a circle

(x-h)^{2}+(y-k)^{2}=r^{2}

where (h, k) is the center of the circle and r is the radius of the circle.

Here, h = 6, k = 4 and r = \sqrt{7}

(x-6)^{2}+(y-4)^{2}=(\sqrt{7}) ^{2}

(x-6)^{2}+(y-4)^{2}=7

Hence the standard form of the equation of a circle is (x-6)^{2}+(y-4)^{2}=7.

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3 years ago
Please help I dont get this☺
kvv77 [185]
The top number would be 288. It's upside down btw
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