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4 years ago

Could someone please help with this question

Mathematics

2 answers:

AleksAgata [21]4 years ago

5 0

Aren't you just multiplying both numerator and denominator by 10?

Answer: 50

Fiesta28 [93]4 years ago

3 0

Answer: 50/70
Hope this helps!

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18+24+3+4x6=6x(4+6)=____+_____

serg [7]

One option for the answer would be -(9+9)

3 0

4 years ago

Read 2 more answers

Make sure the answer is correct!!

saul85 [17]

1) 5

2) square root 26

3) 3 pie

4) 2 square root 5

7 0

4 years ago

12. F(x) = 4x squared

Ymorist [56]

Answer:

y-intercept: $y=0$

axis of symmetry: $x=0$

vertex: $(0,0)$

Step-by-step explanation:

To find the y-intercept, set x = 0 and solve for y.

I am assuming f(x) = y

$y=4x^2$

$y=4(0)^2$

$y=0$

The y-intercept of the equation is y = 0.

Now, for the axis of symmetry, you need the equation $x=\frac{-b}{2a}$

In an equation.. $y=ax^2+bx+c$

In this case, there is only an a, so plug in the values into the equation.

$x=\frac{0}{2(4)}$

$x=0$

The axis of symmetry is x = 0.

To find the vertex, change the format of the equation from standard form to vertex form.

Vertex form: $y=a(x-h)^2+k$

The vertex is $(h,k)$

$y=4x^2 = 4(x+0)^2+0$

$(h,k)=(0,0)$

The vertex in this case is (0,0).

Graphing makes things a lot easier. If you can graph it, all you have to do is look at the graph and the answers are all there!

Hope this helped you!

6 0

3 years ago

A round trip in a helicopter lasted 4 1/2 hours. The average rate going was 160 kilometers per hour. the average rate returning

aalyn [17]

hm not sure tbh lol but try google as a source

8 0

3 years ago

15. Two methods are used to predict how many customers will call in for help in the next four days. The first method predicts th

Marizza181 [45]

Answer:

Method 1 has bigger forecast bias.

Step-by-step explanation:

We are given the following information in the question:

Actuals:

23, 10, 15, 19

Method 1 prediction:

23, 5, 14, 20

Residuals = Predicted - Actuals

Sum of square of errors:

$=(23-23)^2+(5-10)^2+(14-15)^2+(20-19)^2\\= 27$

Mean squared error:

$\dfrac{\text{Sum of squares}}{n} = \dfrac{27}{4} = 6.75$

Method 2 prediction:

20, 13, 14, 20

Residuals = Predicted - Actuals

Sum of square of errors:

$=(20-23)^2+(13-10)^2+(14-15)^2+(20-19)^2\\= 20$

Mean squared error:

$\dfrac{\text{Sum of squares}}{n} = \dfrac{20}{4} = 5$

Since, mean square error of method 2 is less as compared to method 1, method 1 has bigger forecast bias.

4 0

4 years ago