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bija089 [108]
3 years ago
12

How do you find the side length of a triangle?

Mathematics
2 answers:
-Dominant- [34]3 years ago
5 0
If the triangle was a right triangle, then you can use the Pythagorean theorem to find the lengths.
Wewaii [24]3 years ago
3 0
ItsIf the triangle was a right triangle, then you can use the Pythagorean theorem to find the lengths.
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8x – 20 is the correct simplified expression for 4(2x – 5). Explain how to verify the simplified expression.
ziro4ka [17]
Yes, because 4 times 2 is 8(x) and 4 times 5 is 20.
8 0
3 years ago
Read 2 more answers
Help me with this <br> !!!!
Murrr4er [49]

Answer:

<em>a = 17</em>

Step-by-step explanation:

5a = a + 68

5a - a = 68

4a = 68

a = 68 / 4

a = 17

3 0
3 years ago
3) Given P = 5y , find the positive values of x and y that will give P its maximum value if ^2 + 5 = 7.
Furkat [3]

Answer:

were the hell is x

Step-by-step explanation:

where is x in it holy........

6 0
3 years ago
Please help! (I'll give brainliest to the first right answer.)
-BARSIC- [3]

Answer:

1. initial point is (2, 4)

reflected point is (-2, 4)

the coordinates are similar because they involve the same numbers, however, with the reflection across the Y axis, the X point became negative.

2. initial point is (2, 4)

reflected point is (2, -4)

again, same numbers but the X value becomes negative

Hope this helps!

4 0
3 years ago
Read 2 more answers
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
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