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ludmilkaskok [199]
3 years ago
14

Image point B (4,-8) was transformed using the translation (x-2,y+3) what were the coordinates of B?

Mathematics
2 answers:
Kryger [21]3 years ago
6 0

Answer: (6, -11)

Step-by-step explanation:

PilotLPTM [1.2K]3 years ago
5 0
The coordinates of the image point are given to be B(4, -8). We are to find the coordinates of pre-image that is the coordinates before the translation.

The translation made was (x-2, y+3) 

This means, the x coordinate was moved 2 units to left and y coordinate was moved 3 units above. 

So, the coordinates of original point will be, 2 units to right of B and 3 units down of B.

So the coordinates will be (6, -11)
 
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Hoochie [10]
By synthetic division,

-5  |  1    -6    -42    79
.    |        -5     55   -65
- - - - - - - - - - - - - - - - - 
.    |  1   -11    13    14

\implies\dfrac{x^3-6x^2-42x+79}{x+5}=x^2-11x+13+\dfrac{14}{x+5}
\implies x^3-6x^2-42x+79=(x^2-11x+13)(x+5)+14

When x=-5, you're left with a remainder of 14.
5 0
3 years ago
If you know that log5 (2) - log5 (12) = 0, which of the following is false?
garri49 [273]

Answer:

B

Step-by-step explanation:

A is correct because log_5(12) was added on both sides, which is supported by the Additive Property of Equality

C is correct because the Quotient Property of Logarithms states that log_bM-log_bN=log_b(\frac{M}{N} )

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D is correct because using the fact that log_5x=log_512 it is easy to figure out that x=12

For B, there is no property supporting that statement.

8 0
3 years ago
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Step-by-step explanation:

4 0
3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

X^2-3x+27=8x-3

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Is that what you are looking for??

Hope that helps feel free to ask more questions


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