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blagie [28]
4 years ago
9

Help with this question??

Mathematics
1 answer:
Reika [66]4 years ago
3 0

Answer:

3

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

here [ a, b ] = [ 0, 2 ] and from the graph

f(b) = f(2) = 0

f(a) = f(0) = - 6, hence

average rate of change = \frac{0-(-6)}{2-0} = \frac{6}{2} = 3

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According to the rational root theorem, which is a factor of the polynomial f(x)=3x^3-5x^2-12x+20?
MakcuM [25]

Answer:

(x-2), (x+2), (3x-5)

Step-by-step explanation:

Factors of 3: ±1, ±3

Factors of 20: ±1, ±2, ±4, ±5, ±10, ±20

Possible factors of the polynomial: ±1, ±2, ±3, ±4, ±5, ±10, ±20, .... (there's a lot more but you probably do not need to list them all)

Pick a number to divide the polynomial by (I picked 2)

(3x³-5x²-12x+20)÷(x-2) = 3x²+x-10

So (x-2) is a factor of f(x) = 3x³-5x²-12x+20

Factor 3x²+x-10 = (3x-5)(x-2) these are the other factors of f(x) = 3x³-5x²-12x+20

4 0
3 years ago
39. State the equation for the line described below.
devlian [24]

Answer:

Step-by-step explanation:

39). y = -\frac{7}{8} x + 3

40). m = \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

y - y_{1} = m( x - x_{1} )

(- 7, 5)

( - 12, 4)

m = ( 4 - 5 ) / ( - 12 + 7) = 1/5

y - 5 = (1/5)(x + 7) ⇒ y = \frac{1}{5} x + 6.4

8 0
3 years ago
Amanda and her group of friends spent a total of $35.50 on 7 hot dogs and 6 cheese burgers. Greg and his group of friends spent
Alexeev081 [22]
7h + 6b = 35.50
5h + 6b = 30.50

The difference between the 2 totals spent is $5, and there were the same number of burgers, but 2 fewer hotdogs. So $5/2 = $2.50, the cost of a hot dog. Substitute that into the equations to solve for burgers (b)

5(2.50) + 6b = 30.50
12.50 + 6b = 30.50
6b = 18
b = 3

Check the work:
7(2.50) + 6(3) =
17.50 + 18 = 35.50
8 0
3 years ago
Need help please and thanks​
madreJ [45]

Answer:

2. n = 11

4. g = -2

6. t = 21

8. n = 4

10. y = -1

Step-by-step explanation:

2. 63  = -3(1 - 2n)

Dividing both the side by negative 3 we get

-21=1-2n\\2n=1+21\\2n=22\\n=\frac{22}{2} \\\therefore n=11

4. -g + 2(3 + g) = -4(g + 1)

First we will open the bracket by distributive property A( B +C) = AB + AC

-g+2\times 3 + 2\times g = -4\times g + -4\times 1\\-g+6+ 2g=-4g-4\\\textrm{we will take all the g term the left side and the constant to the right side}\\4g-g+2g=-6-4\\5g=-10\\g=\frac{-10}{5}\\\therefore g=-2

6.-3(t +5 ) + (4t + 2) = 8

Using distributive property A( B +C) = AB + AC we get

-3\times t + -3\times 5 + 4t + 2=8\\-3t-15+ 4t + 2=8\\t=8+15-2\\t=21\\\therefore t=21\\

8. -8 - n = -3(2n -4)

Using distributive property A( B +C) = AB + AC we get

-8 - n = -3\times 2n - -3\times4\\-8-n=-6n+12\\\textrm{all the n terms to the left inside and the constant of the right-hand side}\\6n-n=8+12\\5n=20\\n=\frac{20}{5}\\ \therefore n= 4

10. -4( 2 - y) + 3y = 3(y - 4)

Using distributive property A( B +C) = AB + AC we get

-4\times 2 --4\times y + 3y = 3\times y -3\times 4\\-8+4y+3y =3y-12\\\textrm{all the y terms to the left side and the constant to the right side}\\4y+3y-3y=-12+8\\4y=-4\\y=\frac{-4}{4}\\ \therefore y=-1

7 0
4 years ago
Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

4 0
1 year ago
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