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Alik [6]
3 years ago
8

A car increases, then decreases, its speed. Which table could represent the speed of the car? A 2-column table with 5 rows. The

first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 43, 41, 42, 43. A 2-column table with 5 rows. The first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 47, 49, 48, 47. A 2-column table with 5 rows. The first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 45, 45, 43, 41. A 2-column table with 5 rows. The first column is labeled time (minutes) with entries 5, 6, 7, 8, 9. The second column is labeled speed (miles per hour) with entries 45, 43, 41, 41, 41.
Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

The speed increases (45—>47—>49) then decreases (48—>47) over time.

Step-by-step explanation:

HOPE THIS HELPED ✨

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4 years ago
What is the distance in miles, between Joe's home and the park? Round answers to the nearest tenth
Svetlanka [38]
You're on the right track! Now that you have drawn a right triangle with the hypotenuse as the segment from Joe's home to the Park, we can use Pythagorean Theorem to solve for the hypotenuse. 

Pythagorean Theorem = a squared + b squared = c squared
A and B are the legs, and C is the hypotenuse. We can find the legs be calculating how many units they are. 

2 - (-1) = 3
3 - 1 = 2

Pythagorean Theorem = 3 squared + 2 squared = c squared
= 9 + 4 = c squared
= 13 = c squared
= \sqrt{13} = c

The square root of 13 is around 3.6, so Joe's house is approximately 3.6 miles away from the park.
8 0
3 years ago
I NEED HELP! I've failed this test twice and need to get it right. HELP PLEASE!
vlada-n [284]

Answer:

180

Step-by-step explanation:

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to get the C, you need to subtract 180 degrees bt 127 degrees

180 - 127 = C

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3 years ago
13. y =<br> -x2 + 12x - 5<br> Axis of symmetry (aos):
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Answer:

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