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pickupchik [31]
3 years ago
5

HELP PLEASE!

Mathematics
1 answer:
amid [387]3 years ago
7 0
D. 60

when subtracting a negative from a positive use KCC 
K eep
C hange
C hange

you keep the first number change the subtraction to a addition and make the negative a positive

35-(-25)
=======
35+(-25)
=======
35+25
=======
60
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1. Delia purchased a new car for $23,350. This make and model straight line depreciates to zero after 13 years.
frosja888 [35]

Answer:

a. y-intercept = 23350 and x-intercept = 13

b. m = -\frac{23350}{13}

c. y = -\frac{23350}{13}x + 23350

Step-by-step explanation:

Given

Years = 13

Total\ depreciation = \$23350

Solving (a): The x and y intercepts

The y intercept is the initial depreciation value

i.e. when x = 0

This value is the value of the car when it was initially purchased.

Hence, the y-intercept = 23350

The x intercept is the year it takes to finish depreciating

i.e. when y = 0

From the question, we understand that it takes 13 years for the car to totally get depreciated.

Hence, the x-intercept = 13

Solving (b): The slope

The slope (m) is the rate of depreciation per year

This is calculated by dividing the total depreciation by the duration.

So:

m = \frac{23350}{13}

Because it is depreciation, it means the slope represents a deduction.

So,

m = -\frac{23350}{13}

Solving (c): The straight line equation

The general format of an equation is:

y = mx + b

Where

m = slope

b = y\ intercept

In (a), we have that:

y\ intercept = 23350

In (b), we have that:

Slope\ (m) = -\frac{23350}{13}

Substitute these values in y = mx + b

y = -\frac{23350}{13}x + 23350

<em>Hence, the depreciation equation is: </em>y = -\frac{23350}{13}x + 23350<em></em>

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Answer:

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