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WARRIOR [948]
3 years ago
6

If ∠CEF is complementary to ∠DCF, then ∠DCF ≅ ∠FEG.

Mathematics
1 answer:
zimovet [89]3 years ago
7 0
What is the question?
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The steps to get the answer​
jeyben [28]

Answer:

1.7 - 1.5 = 1.2

11.2 - 3.1 = 8.1

Step-by-step explanation:

5 0
3 years ago
What is franks commission if he sales $12,500 of an item and his commission rate is 8.5%
Licemer1 [7]
<h3>SOLUTION:</h3>

Given,

Total sale = $12,500

Rate = 8.5%

Therefore, Commission

= 12,500 × 8.5%

= 12,500 × 85/1000

= 1062.5

5 0
3 years ago
Which expression is equivalent to -6 - ( -2 )<br><br> PLEASE HELP MEEE
katrin [286]

Answer:

-6 +2 = -4

Step-by-step explanation:

Its simple. Whenever you see two negative signs next to each other, they merge into an addition sign "positive".

-6+2 = -4

5 0
3 years ago
Select the correct answer from each drop-down menu.
mixer [17]

Answer:

1. Different

2. More

3. Greater too

Step-by-step explanation:

I'm not completely sure I'm not good with graphs but i hope its right!

5 0
2 years ago
Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
Read 2 more answers
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