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yanalaym [24]
4 years ago
11

Guys if you could help me in #1 #2 #3 #4

Mathematics
1 answer:
dsp734 years ago
5 0
1. $14.1
2. He makes $17.10 per hour, he makes $68.4 in 4 hours, $136.80 in 8, $205.20 in 12 and $273.60 in 16 hours
3. 1 pound makes 16 oz, 16 x 5 = 80 one oz bags 
4. 2,430 miles
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He probability that a randomly selected person refused to answer is 0.162. ​(do not round until the final answer. then round to
4vir4ik [10]

No.


This rate of refusals seems quite low, actually. Some polls are lucky to get a 50% answer rate.

3 0
3 years ago
Clear selection<br>11. The mean of 2,5, (x+1),(x+2), 7 and 9 1 point<br>is 6. Find the median.​
nadezda [96]

Answer:

median= 6.5

Step-by-step explanation:

6= 2+5+x+1+x+2+7+9/6

summing up the values

26+2x=36

collecting like terms,

2x=10

divide both sides by 2

x= 5

5+1=6

5+2=7

so the numbers are 2 5 6 7 7 and 9

the median = 6+7/2

= 6.5

4 0
3 years ago
how many pounds of candy worth $12 per pound should be mixed with candy costing $19 per pound to produce a 70 pound mixture that
sweet-ann [11.9K]

Answer:

40 pounds

Step-by-step explanation:

Given: Cost of a candy (c_1)= \$ 12 per pound

           Cost of candy (c_2) = \$ 19\ per\ pound

           Total amount of mixture of be produced = 70\ pound

           Selling price of mixture = \$ 15 \ per\ pound

Let´s x be the amount of c_1 to be mixed in the mixture.

∴ Cost of c_1 in the mixture = 12x

Next, Cost of c_2 in the mixture = (70 - x)\times 19

And we know the cost of final mixture = 70 \times 15 = 1050

Now, putting all the value in the equation

⇒ 12x + 19 \times (70 - x) = 1050

⇒ 1330 - 7x = 1050

⇒ -7x = -280

∴ x = 40\ pound

∴ 40 pounds of candy worth $12 per pound to be mixed in the mixture.

6 0
3 years ago
Hi. I need help with these questions.<br> See image for question.<br> Answer 14 and 13
irinina [24]

Answer:

  • 13) 36x² + 9x - 4 = 0
  • 14) 21x² + 20x + 100 = 0

Step-by-step explanation:

13.

<h3>Given</h3>

<u>Quadratic equation</u>

  • 4x² - 3x - 4 = 0
  • With the roots of α and β
<h3>To Find </h3>
  • The quadratic equation with roots of 1/(3α) and 1/(3β)
<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

  • α + β = -b/a ⇒ α + β = -(-3)/4 = 3/4
  • αβ = c/a ⇒ αβ = -4/4 = - 1

<u>New equation is:</u>

  • (x - 1/(3α))(x - 1/(3β)) = 0
  • x² - (1/(3α) + 1/(3αβ))x + 1/(3α3β) = 0
  • x² - ((3α + 3 β)/(3α3β))x + 1/(3α3β) = 0
  • x² - ((α + β)/(3αβ))x + 1/(9αβ) = 0
  • x² - (3/4)/(3(-1))x + 1/(9(-1)) = 0
  • x² + 1/4x - 1/9 = 0
  • 36x² + 9x - 4 = 0

===================

14.

<h3>Given</h3>

<u>Quadratic equation</u>

  • 3x² +2x + 7 = 0
  • With the roots of α and β
<h3>To Find </h3>
  • The quadratic equation with roots of α + 1/β and β + 1/α
<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

  • α + β = -b/a ⇒ α + β = -2/3
  • αβ = c/a ⇒ αβ = 7/3

<u>New equation is:</u>

  • (x - (α + 1/β))(x - (β + 1/α)) = 0
  • x² - (α + 1/β + β + 1/α)x + (α + 1/β) (β + 1/α) = 0
  • x² - (α + β + (α + β)/αβ )x + αβ + 1/αβ + 2 = 0
  • x² - (-2/3 - (2/3)/(7/3))x + 7/3 + 1/(7/3) + 2 = 0
  • x² - (-2/3 - 2/7)x + 7/3 + 3/7 + 2 = 0
  • x² + (14 + 6)/21x + (49 + 9 + 42/21) = 0
  • x² + 20/21x + 100/21 = 0
  • 21x² + 20x + 100 = 0
8 0
3 years ago
HELP ME PLEASE GOOD NIGHT
kaheart [24]

Answer:

y=x(t)+y-int

Step-by-step explanation:

Where:

Y= distance

x=speed

t=time

y-int= starting height

If you can post a rate and starting height I can answer part B

Keep in mind if she is traveling down then y-int will be 0<x and the rate will be negative

5 0
3 years ago
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