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3 years ago

Jesse walked 3/4 of a mile last weekend. This weekend he walked 1/2 as far. How far did Jesse walk this weekend?

Mathematics

1 answer:

pantera1 [17]3 years ago

3 0

Answer= 3/8 of a mile

3/4*1/2=3/8

Jesse walked 3/8 a mile this weekend

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Someone help plz? I need some help

Virty [35]

Answer:

$AB =10.8166538264$

$AB \approx10.8$

Step-by-step explanation:

$A( - 5,6),B(1, - 3)$

$A( - 5,6),B(1, - 3) \\ A( { x }_{ 1 } , { y }_{ 1 } ),B( { x }_{ 2 } , { y }_{ 2 } )$

$AB = \sqrt{( { { x }_{ 2 } - { x }_{ 1 } ) }^{2} + {( { y }_{ 2 } - { y }_{ 1 } ) }^{2} }$

$AB = \sqrt{ {(1 - - 5)}^{2} + {( - 3 - 6)}^{2} }$

$AB = \sqrt{ {(1 + 5)}^{2} + { (- 3 - 6)}^{2} }$

$AB = \sqrt{ {(6)}^{2}+ {( - 9)}^{2} }$

$AB = \sqrt{36 + 81}$

$AB = \sqrt{117}$

$AB =10.8166538264$

$AB \approx10.8$

7 0

3 years ago

Use the given graph of f to state the value of each quantity, if it exists. (If an answer does not exist, enter DNE.)

alex41 [277]

Answer:

Hence the answer is given as follows,

Step-by-step explanation:

Graph of y = f(x) given,

(a) $\lim_{x\rightarrow 2^{-}}f(x)=3$

(b) $\lim_{x\rightarrow 2^{+}}f(x)=1$

(c) $\lim_{x\rightarrow 2}f(x)= DNE \left \{ \therefore \lim_{x\rightarrow 2^{-}} f(x)\neq \lim_{x\rightarrow 2^{+}}f(x) \right.$

(d) $f(2)=3$

(e) $\lim_{x\rightarrow 4}f(x) = 4$

(f) $f(4)= DNE.$ { Hole in graph}

Hence solved.

3 0

3 years ago

On Monday, 400 students went on a trip to the zoo. All 9

Marat540 [252]

Answer:

44 students per bus

Step-by-step explanation:

400-4= 396.

396/9=44

3 0

3 years ago

What is the unit fraction of 9/10?

Orlov [11]

$\dfrac{9}{10}=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{15}$

$\dfrac{1}{2}=\dfrac{15}{30}\\\\\dfrac{1}{3}=\dfrac{10}{30}\\\\\dfrac{1}{15}=\dfrac{2}{30}\\\\\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{15}=\dfrac{15}{30}+\dfrac{10}{30}+\dfrac{2}{30}=\dfrac{15+10+2}{30}=\dfrac{27}{30}=\dfrac{9}{10}$

3 0

4 years ago

Given P(E or F) = 0.69, P(E) = 0.49, and P(E and F) = 0.06, what is P(F)?

mamaluj [8]

Answer:

P(F) = 0.26

Step-by-step explanation:

Given:

P(E ∪ F) = 0.69
P(E) = 0.49
P(E ∩ F) = 0.06

Using formula: P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

⇒ P(E ∪ F) = P(E) + P(F) - P(E ∩ F)

⇒ 0.69 = 0.49 + P(F) - 0.06

⇒ 0.69 = 0.43 + P(F)

⇒ P(F) = 0.69 - 0.43

⇒ P(F) = 0.26

7 0

2 years ago