Based on the two different purchases, you can write equations for the price of a hotdog (h) and that of a drink (d). These equations can be solved by your favorite method to find the individual prices.

... 6h +4d = 17.00 . . . . . . Carl's purchase

... 3h +4d = 12.50 . . . . . . Susan's purchase

We can see that the difference in purchase cost (of $4.50) is due entirely to the difference in the number of hotdogs (3). Thus, the price of a hotdog must be

... $4.50/3 = $1.50

The 4 drinks are then ($12.50 -4.50) = $8, so must be $2 each. You don't need to figure the cost of a drink to determine that the appropriate answer choice is ...

... D. $1.50 for a hot dog; $2.00 for a drink.

5 0

3 years ago

Sa = 2(pi)(r)(h) + 2(pi)(r^2) v = (pi)(r^2)(h) find the surface area and the volume.

LenKa [72]

If Sa=2πrh+2π $r^{2}$ v=π $r^{2}h$ then the surface area is π $r^{2} h$ and volume is

(rh-2h)/2r.

Given Sa=2πrh+2π $r^{2} v$ =π $r^{2}h$ .

We have to find surface area and volume from the given expression.

Volume is basically amount of substance a container can hold in its capacity.

First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.

2πrh+2π $r^{2}$ v=π $r^{2}$ h

Keeping the term containing v at left side and take all other to right side.

2π $r^{2}$ v=π $r^{2}h$ -2πrh

v=(π $r^{2}$ h-2πrh)/2π $r^{2}$

v=π $r^{2} h$ /2π $r^{2}$ -2πrh/2π $r^{2}$

v=h/2-h/r

v=h(r-2)/2r

Put the value of v in Sa=2πrh+2π $r^{2} v$

Sa=2πrh+2π $r^{2}$ *h(r-2)/2r

=2πrh+2πrh(r-2)/2

=2πrh+πrh(r-2)

=2πrh+π $r^{2}$ h-2πrh

=π $r^{2}$ h

Hence surface area is π $r^{2}$ h and volume is h(r-2)/2.

Learn more about surface area at brainly.com/question/16519513

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6 0

2 years ago