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4 years ago

Describe a real world situation that can be represented by the quotient negative 85 divided by 15?

1 answer:

5 0

Mark owes sally 85.00$ he finds 14 friends to help him pay her back. How much does each friend need to pay? (This includes mark)

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0=9 (k-2/3)+33<br>solve for k

vaieri [72.5K]

Your answer would be -3

4 0

3 years ago

The product is 63. the sum of the factors is 16. their differences is 2. what are the factors?

____ [38]

9 and 7 will do that job for you.

9 x 7 = 63
and
9 + 7 = 16
and
9 - 7 = 2 .

3 0

3 years ago

Read 2 more answers

Couple more to go, thx for the help >:)

Feliz [49]

Answer: Question 1 is x=9

Question 2 is y=-3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Bus A and Bus B leave the bus depot at 8 am.

LenaWriter [7]

Answer: 10:55

Step-by-step explanation:

Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.

The time the buses will be back at the depot simultaneously will be when:

N(a) * 25mins = N(b) * 35mins

Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.

Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc

Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc

This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.

So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is

at 08:00 + 2:55 = 10:55

6 0

3 years ago

National Textile installed a new textile machine in one of its factories at a cost of $250,000. The machine is depreciated linea

kirill115 [55]

Answer:

The required expression is $y=250,000-24,000 t$

Step-by-step explanation:

Consider the provided information.

National Textile installed a new textile machine in one of its factories at a cost of $250,000.

That means for 0 year the cost of the machine is $250,000.

This can be written as: (0, 250,000)

Over 10 years with a scrap value of $10,000

That means for 10 year the cost of the machine is $10,000.

This can be written as: (10, 10,000)

Now first find the rate of change:

Rate of change=m= $\frac{Rise}{Run}=\frac{10,000-250,000}{10-0}$

Rate of change=m= $\frac{Rise}{Run}=\frac{-240,000}{10}$

Rate of change=m= $\frac{Rise}{Run}=-24,000$

Now use the point-slope form of an equation of a line with the point (0, 250,000), we can find the required expression.

$(y-250,000)=-24,000(t-0)$

$y-250,000=-24,000 t$

$y=250,000-24,000 t$

Hence, the required expression is $y=250,000-24,000 t$

6 0

3 years ago