Ask question

Ask question

All categories

anzhelika [568]

4 years ago

9

The cylindrical drinking glass is holding 150 cubic centimeters of water.What percent of the total volume of the glass is filled

with liquid?

1 answer:

Sveta_85 [38]4 years ago

6 0

volume of the glass:

PI x r^2 x h = 3.14 x 3^2 x 12 = 339.12 cubic cm

150 / 339.12 = 0.442 = 44.2%

Round the answer as needed.

You might be interested in

1. Mother gave donations worth Php 23 900.50 to the Children Foundation and

julia-pushkina [17]

Answer:

What is asked? Total amount left to her.

what are the given? Php 32,097.50 , Php 23,900.50 and Php 60,555.75

what operation should be used to solve the problem? Addition and subtraction

what is the number sentence? Php 23, 900.50+Php32, 097.50=n , Php 60, 555.75 - N = M

what is the complete answer? Php 14,557.75 is the total amount left to her.

7 0

4 years ago

Consider the quadratic ax^2 + bx + c =0, where a,b, and c are rational numbers and the quadratic has two distinct zeroes. If one

Allisa [31]

what makes it irrational is the
$\sqrt{ {b}^{2} - ac } \:$
which does not change from one zero to the other. so if one root its irrational the other one also is. Answer A

8 0

3 years ago

Express as a unit rate: 5 apples for $3.00

Vanyuwa [196]

5/$3.00 is the unit rate. Hope it helps!

3 0

4 years ago

Prove that a cubic equation x 3 + ax 2 + bx+ c = 0 has 3 roots by finding the roots.

evablogger [386]

That's a pretty tall order for Brainly homework. Let's start with the depressed cubic, which is simpler.

Solve

$y^3 + 3py = 2q$

We'll put coefficients on the coefficients to avoid fractions down the road.

The key idea is called a split, which let's us turn the cubic equation in to a quadratic. We split unknown y into two pieces:

$y = s + t$

Substituting,

$(s+t)^3 + 3p(s+t) = 2q$

Expanding it out,

$s^3+3 s^2 t + 3 s t^2 + t^3 + 3p(s+t) = 2q$

$s^3+t^3 + 3 s t(s+t) + 3p(s+t) = 2q$

$s^3+t^3 + 3( s t + p)(s+t) = 2q$

There a few moves we could make from here. The easiest is probably to try to solve the simultaneous equations:

$s^3+t^3=2q, \qquad st+p=0$

which would give us a solution to the cubic.

$p=-st$

$t = -\dfrac p s$

Substituting,

$s^3 - \dfrac{p^3}{s^3} = 2q$

$(s^3)^2 - 2 q s^3 - p^3 = 0$

By the quadratic formula (note the shortcut from the even linear term):

$s^3 = q \pm \sqrt{p^3 + q^2}$

By the symmetry of the problem (we can interchange s and t without changing anything) when s is one solution t is the other:

$s^3 = q + \sqrt{p^3+q^2}$

$t^3 = q - \sqrt{p^3+q^2}$

We've arrived at the solution for the depressed cubic:

$y = s+t = \sqrt[3]{q + \sqrt{p^3+q^2}} + \sqrt[3]{ q - \sqrt{p^3+q^2} }$

This is all three roots of the equation, given by the three cube roots (at least two complex), say for the left radical. The two cubes aren't really independent, we need their product to be $-p=st$ .

That's the three roots of the depressed cubic; let's solve the general cubic by reducing it to the depressed cubic.

$x^3 + ax^2 + bx + c=0$

We want to eliminate the squared term. If substitute x = y + k we'll get a 3ky² from the cubic term and ay² from the squared term; we want these to cancel so 3k=-a.

Substitute x = y - a/3

$(y - a/3)^3 + a(y - a/3)^2 + b(y - a/3) + c = 0$

$y^3 - ay^2 + a^2/3 y - a^3/27 + ay^2-2a^2y/3 + a^3/9 + by - ab/3 + c =0$

$y^3 + (b - a^2/3) y = -(2a^3+9ab) /27$

Comparing that to

$y^3 + 3py = 2q$

we have $p = (3b - a^2) /9, q =-(a^3+9ab)/54$

which we can substitute in to the depressed cubic solution and subtract a/3 to get the three roots. I won't write that out; it's a little ugly.

8 0

4 years ago

1. What is the range of frequencies a human ear can hear?

zubka84 [21]

Answer:

Humans can detect sounds in a frequency range from about 20 Hz to 20 kHz.

(Human infants can actually hear frequencies slightly higher than 20 kHz, but lose some high-frequency sensitivity as they mature; the upper limit in average adults is often closer to 15–17 kHz.)

5 0

4 years ago

Read 2 more answers