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scoundrel [369]
3 years ago
12

Round 111.11111 to the nearest ten thousandth.

Mathematics
2 answers:
aivan3 [116]3 years ago
6 0
111.1 is the answer to the question
ludmilkaskok [199]3 years ago
6 0
111.1111 would be the ten thousandth place
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kati45 [8]

The easiest way to solve this problem is by using the Pythagorean theorem :D

Pythagorean theorem: [-b +- sqrt(b^2 - 4ac)]/2a

5 = a

-1 = b

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therefore, by plugging these values in!

[-(-1) +- sqrt((-1)^2 - 4(5)(6))]/2(5)

[1 +- sqrt(1 - 120)]/10

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[1 +- sqrt(119)*i]10

answers:

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7 0
3 years ago
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umka21 [38]

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3 years ago
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sattari [20]

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I just took the test.

3 0
3 years ago
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lozanna [386]

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5 0
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