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eimsori [14]
3 years ago
6

Help with #7 and #8?

Mathematics
1 answer:
arsen [322]3 years ago
5 0

Answer:

M(6,5) and G(2,9)

Step-by-step explanation:

m = ( \frac{x1 + x2}{2}, \frac{y1 + y2}{2} )

B(3,6)

C(9,4)

m = [(3+9)/2 , (6+4)/2]

= (6,5)

M(5,9)

H(8,9)

G(x,y)

[(x+8)/2 , (y+9)/2]=(5,9)

(x+8)/2 = 5

x+8 = 10

x = 2

(y+9)/2 = 9

y+9 = 18

y = 9

G(2,9)

(Correct me if i am wrong)

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Step-by-step explanation:

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4. B) 6, 34, 27

Step-by-step explanation:

Both #3 and #4 use the same strategy: the two shorter sides' sum has to be greater than the longer side.

#3:

2 + 8 is 10, which is less than 13. So A wouldn't form a triangle.

12 + 22 is 34, which is the length of the longer side. So B wouldn't form a triangle either.

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#4:

17 + 18 is 35, which is greater than 19. So A would form a triangle.

11 + 22 is 33, which is greater than 25. So C would also form a triangle.

5 + 18 is 23, which is greater than 20. So D would form a triangle.

6 + 27 is 33, which is less than 34. So B wouldn't form a triangle.

B. 6, 34, and 27 are the only lengths of the ones shown that don't form a triangle.

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Step-by-step explanation:

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