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QveST [7]
3 years ago
7

What is the simplified form of this expression?

Mathematics
1 answer:
loris [4]3 years ago
8 0
\bf \cfrac{6x+12}{3x-6}\implies \cfrac{6(x+2)}{3(x-2)}\implies \cfrac{6}{3}\cdot \cfrac{(x+2)}{(x-2)}\implies \cfrac{2}{1}\cdot \cfrac{(x+2)}{(x-2)}\\\\\\ \cfrac{2(x+2)}{(x-2)}
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(02.01)Which translation will change figure ABC to figure A'B'C'?
liq [111]

Answer:

4 units right and 3 units up.

Step-by-step explanation:

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=2a%20%7B%20%7D%5E%7B2%7D%20b%20%7B%7D%5E%7B2%7D%20-%207ab%20-%2030" id="TexFormula1" title="2a
yarga [219]

Answer:

(ab - 6)(2ab + 5)

Step-by-step explanation:

Assuming you require the expression factorised.

2a²b² - 7ab - 30

Consider the factors of the product of the coefficient of the a²b² term and the constant term which sum to give the coefficient of the ab- term

product = 2 × - 30 = - 60 and sum = - 7

The factors are - 12 and + 5

Use these factors to split the ab- term

= 2a²b² - 12ab + 5ab - 30 ( factor the first/second and third/fourth terms )

= 2ab(ab - 6) + 5(ab - 6) ← factor out (ab - 6) from each term

= (ab - 6)(2ab + 5) ← in factored form

5 0
3 years ago
The table shows the cost of renting a sound system for a concert. Isabel rents a sound system at 1 p.m. and plans to return it b
leonid [27]

Answer:

56

Step-by-step explanation:

its 56 b

3 0
3 years ago
The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP​
Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d }    = 30

       5(2a  + 4d )d           = 60

       10a    + 20d             = 60

reduce to lowest term to easy calculation by dividing through by 10

                      a + 2d       = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉  = ⁹/₂(2a + 8d )   = 69

        9(2a  + 8d )    = 30 + 69

            18a + 72d   = 99 x 2

            18a + 72d   = 198

divide through by 18 to reduce to lowest time

                a  + 4d    = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

                 a + 2d = 6

                 a + 4d = 11

                     -2d  = -5

                          d = ⁵/₂.

Now substitute  for d to get a

               a  + 2(⁵/₂) = 6

                a + 5       = 6

                           a   = 6 - 5

                            a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0
2 years ago
Given h(x) = 5x − 1, find x if h(x) = 9
mart [117]
I believe x=15. Because you’ll just plug them in
4 0
2 years ago
Read 2 more answers
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