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3 years ago

What are the approximate values of the minimum and maximum points of

1 answer:

7 0

To start off, you can divide the right side of the equation by x to get rid of most of the x's so you get the polynomial x^4 - 10x^2 + 9. This means that f(x) = x^4 - 10x^2 + 9x. By factoring the right side of the equation, you get f(x) = (x^2 - 1)(x^2 - 9). I think the minimum value is 1 and the maximum value is 3.

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A farmer has 24 bushels of apples and can harvest 22 bushels of apples each day?

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Answer:

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2 years ago

if 2 binders of the same size take up 3 inches on the shelf how much space will be needed for 28 of these binders?

Anna [14]

Answer:

Step-by-step explanation:

28x3=84

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3 years ago

a coin is flipped 5 times. we then observe the number of times a coin lands on heads. what is the compliment of the event "at le

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If at least one has to be heads then it would be 1/5

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3 years ago

1) 14 units2 2) 16 units2 3) 17 units2 4) 19 units2

horrorfan [7]

Answer:

<h2>4th option: 19 units2 </h2>

Step-by-step explanation:

<h3>The given figure can be divided as (i) upper rectangle, (ii) lower rectangle </h3>

Then,

(i) Breadth of upper rectangle = 2 units

Length of upper rectangle = 8 - 1 = 7 units

Therefore, 

Area of the upper rectangle = 7 × 2 = 14 units2

(ii) Breadth of lower rectangle = 1 unit

Length of lower rectangle = 5 units

Therefore, 

Area of the lower rectangle = 5 × 1 = 5 units2

Since,

Area of the figure is = Area of upper rectangle + Area of lower rectangle 

= 14 units2 + 5 units2

= 19 units2 (Ans) (4th option)

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2 years ago

A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =

AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have $\mu = 43, \sigma = 4$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 43}{4}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544$

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

4 0

3 years ago