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Mariana [72]
3 years ago
15

Please explain how these are the right answers.

Mathematics
1 answer:
Olin [163]3 years ago
5 0
Hello there,

Your correct answer's is in the attachment.

Hope this helps.

~Jurgen

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F(x)=4(x+2)(x+2)-6 in standard form
ollegr [7]

Answer:

4x^2 + 4x -2

Step-by-step explanation:

Use FOIL to solve (x+2) (x+2)

4(x^2 + 4x +4) - 6

4x^2 + 4x -2

8 0
3 years ago
What is the value of this equation 38>-5x+3>18
Bond [772]
Its called inequality 
8 0
3 years ago
Please help @musiclover10045<br> I have been stuck on this problem like forever
Stella [2.4K]

a) ABD and CBD are Supplementary angles and need to equal 180 degrees

Subtract 117 from 180 for CBD:

CBD = 180 - 117 = 63 degrees


b) In triangles the the shortest side would be opposite the shortest angle.

Since angle D is 56 degrees ( the smallest inside angle) then side BC would be the shortest side.


c) The side opposite the largest angle would be the longest.

Angle B is 63 degrees ( the largest) so side CD is the longest.


3 0
3 years ago
Can you guys please help. I really don't know how to solve this
Nonamiya [84]

The inequalities that can be used to represent this problem are x < 0 or x > 5. On the number line, you will want to place an open circle on both 0 and 5. The open circle signifies that x is not equal to these values, but is greater or less than. On the open circle on 0, draw an arrow pointing left, toward the negative values. On the open circle on 5, draw an arrow pointing right, toward the positive values.

Hope this helps!! :)

3 0
4 years ago
A function is given. h(t) = t2 + 3t; t = −1, t = 2
Arlecino [84]

Answer:

(a) The net change of the function is 12.

(b) The average rate of change of the function 4.

Step-by-step explanation:

The average rate of change of function f(x) over the interval a\leq x\leq b is given by this expression:

average rate of change =  \frac{net \:change \:in \:y}{change \:in \:x} = \frac{f(b)-f(a)}{b-a}

It is a measure of how much the function changed per unit, on average, over that interval.

Given:

h(t)=t^2+3t\\\\t=-1\\t=2

(a) To find the net change of the function, first we calculate the values of h(2) and h(-1)

h(-1)=(-1)^2+3(-1)=-2\\\\h(2)=(2)^2+3(2)=10

The net change is simply the difference

h(2)-h(-1)=10-(-2)=12

(b) The average rate of change takes the net change and divides it by the change in the t value.

\frac{12}{2-(-1)} =\frac{12}{3}=4

5 0
3 years ago
Read 2 more answers
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