All categories

3 years ago

A newspaper carrier can deliver 49 papers in one hour at this rate how many newspaper can the carrier deliver in 3 hours

Mathematics

2 answers:

labwork [276]3 years ago

6 0

The newspaper carrier can deliver 147 newspapers in 3 hours

Ivenika [448]3 years ago

5 0

You would multiply the time by how many newspapers he can deliver. He can deliver 147 in 3 hours. Hope this helps

Have a nice day.

You might be interested in

Please explain me how to solve it cos2x+cos4x ≥0

Sliva [168]

2x + 4x will always be larger or equal to 0.
if x= 0 than it will be equal to 0.
Does this help at all?

3 0

3 years ago

Are the points U, H, and L collinear? U E S H

butalik [34]

Answer:

Yes

Step-by-step explanation:

Collinear means points are lying on the same straight line. U, H, and L are all lying on the line l.

4 0

3 years ago

In a memory experiment, Alice is able to memorize words at a rate given by m '(t)= - 0.009t^2 + 0.6t. In the same memory exper

White raven [17]

Answer:

1) Ben, 2) $\Delta = 2$ , 3) $\dot m = 2.7$ , 4) $\dot M = 2.9$

Step-by-step explanation:

1) Ben has a higher rate of memorization, since the coefficient of the second power is lesser than the one from Alice.

2) The number of words can be estimated by integrating the function:

Alice

$\Delta m = -0.003\cdot (10\,min)^{3} + 0.3\cdot (10\,min)^{2}$

$\Delta m = 27$

Ben

$\Delta M = -0.001\cdot (10\,min)^{3} + 0.3\cdot (10\,min)^{2}$

$\Delta M = 29$

$\Delta = \Delta M - \Delta m$

$\Delta = 2$

3) The average amount of words per minute is:

$\dot m = \frac{27}{10}$

$\dot m = 2.7$

4) The average amount of words per minute is:

$\dot M = \frac{29}{10}$

$\dot M = 2.9$

4 0

3 years ago

Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq

AnnyKZ [126]

Answer:

$(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Step-by-step explanation:

Step(i):-

Given that the function

f(x) = $e^{4x} \sqrt{1+e^{2x} }$

Now integrating on both sides, we get

$\int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx$

= $\int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx$

Step(ii):-

Let $1 + e^{2x} = t$

$e^{2x} = t -1$

$2e^{2x}dx = d t$

$e^{2x}dx = \frac{1}{2} d t$

= $\int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx$

= $\int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }$

= $\frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }$

= $\frac{1}{2} \int\limits {(t^{\frac{1}{2} } t^{1} +t^{\frac{1}{2} } ) } \, dx$

$= \frac{1}{2} \int\limits {(t^{\frac{3}{2} } +t^{\frac{1}{2} } ) } \, dx$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C$

= $\frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C$

= $\frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C$

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

Final answer:-

= $(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C$

3 0

3 years ago

Find the inverse of f(x) = x2 - 5:

Volgvan

Answer:

g(f(x))=x g ( f ( x ) ) = x , f−1(x)=√x+5,−√x+5 f - 1 ( x ) = x + 5 , - x + 5 is the inverse of f(x)=x2−5 f ( x ) = x 2 - 5 .

Step-by-step explanation:

( f ( x ) ) = x , f−1(x)=√x+5,−√x+5 f - 1 ( x ) = x + 5 , - x + 5 is the inverse of f(x)=x2−5 f ( x ) = x 2 - 5 .

5 0

3 years ago