Three times b less than 100 is equal to the product of 6 and b
2 answers:
The equation is : 100 -3b = 6b
The solution: variable b = 11.9
<h3>Further Explanation</h3>One variable linear equation is an equation that has a variable and the exponent number is one. Can be stated in the form:
ax + b = c, where a, b, and c are constants, x is a variable
Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one
Can be stated in the form:
x, y = variable
In the statement of the task:
three times b less than 100 is equal to the product of 6 and b is the same as 100 minus 3 times b equals 6 times b.
If we translate this sentence into equation, :
100 -3b = 6b
This equation belongs to One variable linear equation because there is one variable = b and the exponent number is one
The solution is :
100 = 9b
b = 100 : 9
b = 11.1
<h3>Learn more </h3>the slope-intercept form of the linear equation
a graph of a linear equation
system of linear equations
Keywords : one variable, linear equation , product, less than, equal to, two variable, constants
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Solve the trigonometric equation:
Restriction for the solution:
Square both sides of (i):
![\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2%5Ccdot%20%281-sin%5E2%5C%2Cx%29-sin%5C%2Cx%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2-2%5C%2Csin%5E2%5C%2Cx-sin%5C%2Cx%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B-%5C%2C%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2%5C%2Csin%5E2%5C%2Cx%2Bsin%5C%2Cx-2%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7Bsin%5C%2Cx%5Ccdot%20%5Cleft%5B2%5C%2Csin%5E2%5C%2Cx%2Bsin%5C%2Cx-2%20%5Cright%5D%3D0%7D)
Let
So the equation becomes
Solving the quadratic equation:
You can discard the negative value for t. So the solution for (ii) is
Substitute back for t = sin x. Remember the restriction for x:
where k is an integer.
I hope this helps. =)
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Solve the trigonometric equation:
Restriction for the solution:
Square both sides of (i):
Let
So the equation becomes
Solving the quadratic equation:
You can discard the negative value for t. So the solution for (ii) is
Substitute back for t = sin x. Remember the restriction for x:
where k is an integer.
I hope this helps. =)