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3 years ago

If melba rode her bike 7/8 miles in 1/4hour. what is the unit rate in miles per hour

Mathematics

1 answer:

kari74 [83]3 years ago

4 0

3.5 miles per hour. 7/8 (.875) divided by 1/4 (.25) equals 3.5. Hope this helps!

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Answer:

$\dfrac{\pi}{4},\dfrac{3\pi}{4}$

Step-by-step explanation:

$2\sin^2(\theta)=1$

Divide both sides by 2:

$\sin^2(\theta)=\dfrac{1}{2}$

Take the square root of both sides:

$\sin(\theta)=\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2}$

The only two places on the unit circle where the y value of the point is $\dfrac{\sqrt{2}}{2}$ are at:

$\dfrac{\pi}{4},\dfrac{3\pi}{4}$

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3 years ago

Which statement is true regarding the graphed functions? f(0) = g(0) X f(-2) = g(-2) f(0) = g(-2) f(-2) = g(0)

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Step-by-step explanation:

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3 years ago

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7.083,7.2,7.21

Step-by-step explanation:

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3 years ago

The relationship between the actual air temperature x (in degrees Fahrenheit) and the temperature y adjusted for wind chill (in

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3 years ago

The population of a certain country in 1997 was 288 million people. In addition, the population of the country was growing at a

Crazy boy [7]

Answer:

a) In the year 1998 with 3 days, 2 hours, 44 minutes and 18.1006141 seconds

b) In the year 1998 with 19 days, 18 hours, 5 minutes and 35.10875472 seconds

Step-by-step explanation:

a) To know the time when the population will be 305 million people, we need to isolate the variable t in the equation, $P(t)=288(1.009)^{t-1997}$

So we isolate t with the property of logarithms that allow us go down the exponent, applying in both sides of the equation

For this subsection the value of P is equal to 305 million people

$Ln(305)=Ln[(288)(1.009)]^{t-1997}$

$Ln(305)=(t-1997)*Ln[(288)(1.009)]$

Now, we can isolate the value of t

$\frac{Ln(305)}{Ln[(288)(1.009)]} =t-1997$

$\frac{Ln(305)}{Ln[(288)(1.009)]}-1997 =t$

$t=1998.008531776402$

So to know the exact date we multiply the number after the point, that is 0.008531776402 for the number of days that have 1 year, equal to 365 days

0.008531776402*365= 3.114098387 days

then the number after the point, that is 0.114098387 will be multiply for the number of hours that have 1 day

0.114098387*24= 2.738361282 hours

then the number after the point, that is 0.738361282 will be multiply for the number of minutes that have 1 hour

0.738361282*60= 44.3016769 minutes

Finally, the number after the point, that is 0.3016769 will be multiply for the number of seconds that have 1 minute

0.3016769*60= 18.1006141 seconds

And we obtain that the time, when the population of the country is 305 million people, is in the year 1998 with 3 days, 2 hours, 44 minutes and 25.152 seconds

b) For calculate the time when the population is 395 million people, we do the same process we did in the subsection a)

$Ln(395)=Ln[(288)(1.009)]^{t-1997}$

$Ln(395)=(t-1997)*Ln[(288)(1.009)]$

Now, we can isolate the value of t

$\frac{Ln(395)}{Ln[(288)(1.009)]} =t-1997$

$\frac{Ln(395)}{Ln[(288)(1.009)]}-1997 =t$

$t=1998.05412021527$

0.05412021527*365= 19.75387857 days

0.75387857 *24= 18.09308577 hours

0.09308577*60= 5.585145912 minutes

0.585145912*60= 35.10875472 seconds

And we obtain that the time, when the population of the country is 395 million people, is in the year 1998 with 19 days, 18 hours, 5 minutes and 35.10875472 seconds

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3 years ago