the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.
multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.
so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5 <----- notice, current coefficient times 3 divided by 4+1.
anyhow, with that out of the way, lemme proceed in this one.

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.
so then, we know that the expanded 2nd term is 24x therefore

we also know that the expanded 3rd term is 240x², therefore we can say that

but but but, we know what "n" equals to, recall above, so let's do some quick substitution
![\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20a%5E2n%5E2-a%5E2n%3D480%5Cqquad%20%5Cboxed%7Bn%3D%5Ccfrac%7B24%7D%7Ba%7D%7D%5Cqquad%20a%5E2%5Cleft%28%20%5Ccfrac%7B24%7D%7Ba%7D%20%5Cright%29%5E2-a%5E2%5Cleft%28%20%5Ccfrac%7B24%7D%7Ba%7D%20%5Cright%29%3D480%20%5C%5C%5C%5C%5C%5C%20a%5E2%5Ccdot%20%5Ccfrac%7B24%5E2%7D%7Ba%5E2%7D-24a%3D480%5Cimplies%2024%5E2-24a%3D480%5Cimplies%20576-24a%3D480%20%5C%5C%5C%5C%5C%5C%20-24a%3D-96%5Cimplies%20a%3D%5Ccfrac%7B-96%7D%7B-24%7D%5Cimplies%20%5Cblacktriangleright%20a%20%3D%204%5Cblacktriangleleft%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20n%3D%5Ccfrac%7B24%7D%7Ba%7D%5Cimplies%20n%3D%5Ccfrac%7B24%7D%7B4%7D%5Cimplies%20%5Cblacktriangleright%20n%3D6%20%5Cblacktriangleleft)
Use a class pad in order to get what you're looking for.
Aas is what you would use because it would be giving you two angles and only one side that isn't in between the two angles.
Answer:
lines r and s
Step-by-step explanation:
we know that
<u><em>Alternate interior angles</em></u> are formed when a transversal passes through two lines. The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles.
When the lines are parallel, the alternate interior angles are equal
so
In this problem
If lines r and s are parallel
then
m∠4=m∠5 ----> by alternate interior angles
Answer: x = 8
Step-by-step explanation:
Since, RTS is the equilateral triangle.
Thus, RT= TS = SR
And,
( By the property of the equilateral triangle.)
Here, Given ∠ RST = (7 x + 4)°
And, ∠ RTS = (8y +12)°
Therefore, (7 x + 4)° = 60°
⇒ 7 x = 56
⇒ x = 8