The area of the given right triangle is: 22.5 cm².
<h3>How to Find the Area of a Right Triangle?</h3>
The area of a right triangle with a base of "b" and an height of "h" can be determined using the following formula:
Area of triangle = 1/2bh = 1/2(base)(height).
Given that the right triangle has the following dimensions:
Height (h) = 5 cm
Base (b) = 9 cm
Area of triangle = 1/2bh = 1/2(5)(9)
Area of triangle = 1/2(45)
Area of triangle = 22.5 cm²
Thus, the area of the right triangle is: 22.5 cm².
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So you have a pole that is 10 feet tall that has a rope that goes from the top to the ground, the rope being 30 degrees to the ground... You can draw a right triangle using these dimensions. Now that you have a triangle, you look at where your 30degree angle is related to the side whose length you know and the side whose length you wish to find. The side you know is opposite from the 30 degrees while the side you want to find is the hypotenuse, for it goes down at an angle. You will use the opposite and hypotenuse sides, so, according to SOH CAH TOA, you will be using sin.

plug in those values and solve for your hypotenuse.
The easiest way to do this is if you knew the identities for special right triangles like the 30 60 90 triangles or the 45 45 90 triangles, but I showed you how to solve for your sides even if they're not special
A vertical stretching is the stretching of the graph away from the x-axis.
A vertical compression is the squeezing of the graph towards the x-axis.
A compression is a stretch by a factor less than 1.
For the parent function y = f(x), the vertical stretching or compression of the function is a f(x).
If | a | < 1 (a fraction between 0 and 1), then the graph is compressed vertically by a factor of a units.
If | a | > 1, then the graph is stretched vertically by a factor of a units.
For values of a that are negative, then the vertical compression or vertical stretching of the graph is followed by a reflection across the x-axis.
Thus, the equation with the widest graph is 0.3x^2.