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3 years ago

For f(x) =2x+1 and g(x)=- squt -7 find (g/f)(x)

Mathematics

1 answer:

Mariana [72]3 years ago

4 0

Answer:

Step-by-step explanation:

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yler and Bethany have 240 feet of fencing with which to build a garden. Tyler wants the garden to be in the shape of a square, w

Sidana [21]

To get which design would have maximum area we need to evaluate the area for Tyler's design. Given that the design is square, let the length= xft, width=(120-x)
thus:
area will be:
P(x)=x(120-x)
P(x)=120x-x²
For maximum area P'(x)=0
P'(x)=120-2x=0
thus
x=60 ft
thus for maximum area x=60 ft
thus the area will be:
Area=60×60=3600 ft²
Thus we conclude that Tyler's design is the largest. Thus:
the answer is:
Tyler’s design would give the larger garden because the area would be 3,600 ft2.

4 0

3 years ago

What is the answer to 6w^2-24w-126

Dafna1 [17]

Answer:

6(w+3)(w-7)

Sorry if this is the wrong answer. But I hope you get a good grade on your test.

7 0

4 years ago

An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba

madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

X = a person is overweight

Y = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688$

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

$P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312$

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0

3 years ago

Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 51 km/h. After five hou

Alex777 [14]

The question is asking to write and equation by using the two variable in the standard form that ca be used to describe the velocity of thecar at different times and base on my calculation, I would say that the answer would be v=4t+39. I hope you are satisfied with my answer and feel free to ask for more

5 0

3 years ago

What is the area of this triangle

Julli [10]

By the looks of it the hieght is 7 and base is 6 so

A= 1/2(6)(7)
A= 1/2(42)
A= 21

4 0

3 years ago