Answer:
0 = 6
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3(m−1)=5m+3−2m
(3)(m)+(3)(−1)=5m+3+−2m (Distribute)
3m+−3=5m+3+−2m
3m−3=(5m+−2m)+(3) (Combine Like Terms)
3m−3=3m+3
3m−3=3m+3
Step 2: Subtract 3m from both sides.
3m−3−3m=3m+3−3m
−3=3
Step 3: Add 3 to both sides.
−3+3=3+3
0=6
Answer:
Step-by-step explanation:
There is nothing I can solve
We have four two cards in 52 cards and four ten cards in the same playing cards
to get our first four cards we choose one from the whole set of 52 cards
but to get the next card with ten we choose them out of 51 because we took the first card with value two and we have not replaced it
this gives us
4/52*4/51=0.006
Answer:
sample size n would be 149305 large
Value of n (149305) is too high, this will be the practical problem with attempting to find this confidence interval
Step-by-step explanation:
Given that;
standard deviation α = 150 min
confidence interval = 99%
since; p( -2.576 < z < 2.576) = 0.99
so z-value for 99% CI is 2.576
E = 1 minutes
Therefore
n = [(z × α) / E ]²
so we substitute
n = [(2.576 × 150) / 1 ]²
n = [ 386.4 ]²
n = 149304.96 ≈ 149305
Therefore sample size would be 149305 large
Value of n is too high, that would be the practical problem with attempting to find this confidence interval
