Consider the prime factorization of 20!.
The LCM of 1, 2, ..., 20 must contain all the primes less than 20 in its factorization, so
where is some integer not divisible by any of these primes.
Compare the factorizations of the remaining divisors of 20!, and check off any whose factorizations are already contained in the product of primes above.
- missing a factor of 2
- ✓
- missing a factor of 2²
- missing a factor of 3
- ✓
- missing a factor of 2
- ✓
- ✓
- missing a factor of 2³
- missing a factor of 3
- missing a factor of 2
From the divisors marked "missing", we add the necessary missing factors to the factorization of , so that
Then the LCM of 1, 2, 3, …, 20 is
The Answer is A. Plug in the inequalities on desmos
Answer:
min- 520 ml
max- 780 ml
Step-by-step explanation:
Answer:
It is 89.10
Step-by-step explanation:
Hope this helps.
Answer:
Option D.
Step-by-step explanation:
It is given that triangle ABC reflected in the y axes so that the image of triangle ABC is triangle A'B'C'.
Let A(a,b) and B(c,d). So, after reflection A'(-a,b) and B'(-c,d).
Using distance formula,
So,
We know that reflection is rigid transformation, it means figure and its image must be congruent.
If triangle ABC is read clockwise, then after reflection triangle A'B"C' is read anticlockwise.
Since statements I, II and IV are true, therefore the correct option is D.