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vovikov84 [41]
3 years ago
8

Find an equation of the line that passes through the points (1 2) and perpendicular to the line 2y-x=4

Mathematics
1 answer:
Ratling [72]3 years ago
3 0
Steps to find the equation
1. Find the slope
2. Insert slope into the general equation
3. Find y-intercept
4. Insert -intercept into the equation found in step 2
And you get the equation of the line

----------------------------------------------------------------------------------------------
Find the slope
----------------------------------------------------------------------------------------------
2y - x = 4

----------------------------------------------------------------------------------------------
Rewrite into the form y = mx + c
----------------------------------------------------------------------------------------------
2y = x + 4
y = 1/2 x + 2

Slope = 1/2
Perpendicular slope = -2 (negative reciprocal)

----------------------------------------------------------------------------------------------
Insert slope into the equation
----------------------------------------------------------------------------------------------
y = mx + c
y = -2x + c

----------------------------------------------------------------------------------------------
Find y-intercept
----------------------------------------------------------------------------------------------
y = -2x + c
At point (1, 2)
2 = -2(1) + c
2 = -2 + c
c = 4

----------------------------------------------------------------------------------------------
Insert y-intercept into the equation y = -2x + c
----------------------------------------------------------------------------------------------
y = -2x + 4

----------------------------------------------------------------------------------------------
Answer: y = -2x + 4
----------------------------------------------------------------------------------------------
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