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pogonyaev
3 years ago
6

Need help with this one

Mathematics
1 answer:
tiny-mole [99]3 years ago
6 0

Answer: The perimeter of triangle ABC is p = 21.8 units

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Can someone help me with this
Morgarella [4.7K]

Answer:

FG=30

Step-by-step explanation:

Since we know that Point G is on the Segment FH, it doesn't really matter where G is, but we can know for certain that:

FH=FG+GH

We are given that FH is 4x, GH is x, and FG is 2x+10. Substitute:

4x=(2x+10)+x

Solve for x. On the right, combine like terms:

4x=3x+10

Subtract 3x from both sides:

x=10

So, the value of x is 10.

To find the value of FG, substitute 10 into its x:

FG=2x+10\\FG=2(10)+10

Multiply:

FG=20+10

Add:

FG=30

And we're done!

6 0
3 years ago
A survey of 2,000 doctors showed that an average of 3 out of 5 doctors use brand X aspirin. How many doctors use brand X aspirin
Ber [7]

2000 times 0.60 = 1200 doctors

6 0
3 years ago
Read 2 more answers
Whats has the same slope of 6x-3y=9
Crank

Answer:


Step-by-step explanation:

when you put it into slope intercept form you get

y=2x-3

2 is the slope, so

y=2x+3 would have the same slope which means these lines are parallel.

6 0
3 years ago
108÷9⋅(−12)÷6−(100÷5)
pochemuha

Answer:

-44

Step-by-step explanation:

5 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
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