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Mamont248 [21]
3 years ago
7

The task:Find the radius or diameter of each circle with the given dimensions 2. d=4 ft​

Mathematics
1 answer:
cupoosta [38]3 years ago
4 0

Answer:

If the diameter us 4, the radius would be 2.

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The volume, V, of a right cone varies jointly with the square of the radius of the base, r, and the height, h. When r = 6 and h
Sveta_85 [38]

Answer:

V=πr^2(h/3)

Step-by-step explanation:

V=π6^2(8/3)

6 0
3 years ago
Add (13x – 4) and (–6x + 15)
kompoz [17]

(13x – 4) + (–6x + 15) =

13x - 4 - 6x + 15 =

7x + 11

4 0
3 years ago
Tell whether the ordered pair is a solution of the linear system. (-4,-6); -3x+y=6, -2x+y=-8
harkovskaia [24]
Plug them in... -4=x -5=y

-3x-4+-6=6 (check)
-3x-4=12-6=6 (ordered pair works with this equation)

-2x-4+-6=-8 (check)
-2x-4=8-6=2 (ordered pair does not work with this equation)

Therefore the ordered pair IS NOT the solution.

Hope this helps :)

8 0
3 years ago
cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta
NikAS [45]
First calculate \sin\theta.

\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\&#10;\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}
5 0
3 years ago
Read 2 more answers
Explain how you simplfy 5(4i - 3m) + 2m
Galina-37 [17]

Answer:

20i - 13m. look at the picture

5 0
3 years ago
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