3 years ago

The task:Find the radius or diameter of each circle with the given dimensions 2. d=4 ft

Mathematics

1 answer:

cupoosta [38]3 years ago

4 0

Answer:

If the diameter us 4, the radius would be 2.

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The volume, V, of a right cone varies jointly with the square of the radius of the base, r, and the height, h. When r = 6 and h

Sveta_85 [38]

Answer:

V=πr^2(h/3)

Step-by-step explanation:

V=π6^2(8/3)

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3 years ago

Add (13x – 4) and (–6x + 15)

kompoz [17]

(13x – 4) + (–6x + 15) =

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Plug them in... -4=x -5=y

-3x-4+-6=6 (check)
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Therefore the ordered pair IS NOT the solution.

Hope this helps :)

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3 years ago

cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

NikAS [45]

First calculate $\sin\theta$ .

$\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}$

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

$\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\
\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}$

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3 years ago

Read 2 more answers

Explain how you simplfy 5(4i - 3m) + 2m

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Answer:

20i - 13m. look at the picture

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3 years ago

The task:Find the radius or diameter of each circle with the given dimensions 2. d=4 ft​

The task:Find the radius or diameter of each circle with the given dimensions 2. d=4 ft