(6.02x10^23)(9.63x10^-2)
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The randomly selected subject is given bone density test which are normally distributed with mean =0 and standard deviation =1. It means bone density test score is standard normal variable.
The probability that a given score is less than 2.23
P(z < 2.23)
Using z score table to find probability below z=2.23
P(z < 2.23) = 0.9871
The probability that a given score is less than 2.23 is 0.9871
