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Elena L [17]
3 years ago
13

Find all the powers of 4 in the range 4 through 1000

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0
Powers of 4 are like 4^1, 4^2, 4^3 and so on
remember that 4^x means 4 times itself x times for example
4^3=4 times iteslef 3 times=4 times 4 times 4

so the multipules of the powers of 4 are just 4 times of the previous
so we will list

4^1=4
4^2=16
4^3=64
4^4=256
4^5=1024

1024 is already more than 1000 so the list stops and is
1,16,64,256
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Carlos wrote three numbers between 0.33 and 0.34 what numbers could Carlos have written?
sergij07 [2.7K]

the correct answer is:

Carlos could have written 0.333, 0.334, and 0.3335.


side notes:

hope this helps or is correct!

4 0
3 years ago
Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr
drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

AC^2= AB^2+BC^2

\Rightarrow (x+3)^2=x^2+8^2

\Rightarrow x^2+6x+9=x^2+64

\Rightarrow 6x=64-9=55

\Rightarrow x=55/6=9.17 chi.

Hence, the height of the pole, AB=x=9.17 chi,

and the length of the rope, x+3=9.17+3=12.17 chi.

8 0
3 years ago
Solve :3(2x+1)^-1 + 5x=-1<br>​
Finger [1]

hope this is ans . Brother

8 0
3 years ago
25
Cloud [144]
If you are asking if your work is good,thn yes,you are right

7 0
3 years ago
Three rays have a common vertex on a line. Write and solve equations to find the measures of m and n
lukranit [14]

Answer:

n = 90 - 62

n = 28º

m = 180 - (62 + n + 27)

m = 180 - (62 + 28 + 27)

m = 180 - 117

m = 63º

5 0
3 years ago
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