All categories

2 years ago

What is 5/12 times 1 1/3

Mathematics

1 answer:

vaieri [72.5K]2 years ago

8 0

5/9
5 times 4= 20
12 times 3=36
20/36=5/9

You might be interested in

Write an inequality for the following graph

Tom [10]

Answer:

I am pretty sure it would be B.

7 0

1 year ago

Read 2 more answers

Arte-miy333 [17]

The answer might be B

7 0

2 years ago

PLEASE HELP IM CONFUSED! Find what the measurements of angles a-c are and state the reason

nata0808 [166]

Answer:

<a = 90° (180-90 supplementary angle)

<b = 90° (180-90 supplementary angle)

<d = 48° (180-132 supplementary angle)

<e = 132° (opposite angle)

<c = 42° (interior angles of a triangle equal 180. 180-48-90=42)

Step-by-step explanation:

<a = 90° (180-90 supplementary angle)

<b = 90° (180-90 supplementary angle)

<d = 48° (180-132 supplementary angle)

<e = 132° (opposite angle)

<c = 42° (interior angles of a triangle equal 180. 180-48-90=42)

8 0

2 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

2 years ago

Five and thirty-nine thousandths in standard decimal form

Nesterboy [21]

Answer:

Five and thirty-nine thousandths in standard decimal form is

5.039

Hope This Helps!!!

7 0

1 year ago