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3 years ago

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5/9(F-32) < 0 or 5/9(F-32)>5

1 answer:

Anastasy [175]3 years ago

3 0

$\dfrac{5}{9}(F-32) \ \textless \ 0\ \ \ |\cdot\dfrac{9}{5}\\\\F-32 \ \textless \ 0\ \ \ |+32\\\\F \ \textless \ 32\\or\\\dfrac{5}{9}(F-32) \ \textgreater \ 5\ \ \ |\cdot\dfrac{9}{5}\\\\F-32 \ \textgreater \ 9\ \ \ |+32\\\\F \ \textgreater \ 41\\\\Answer:\ F \ \textless \ 32\ or\ F \ \textgreater \ 41\ \to\ F\in(-\infty;\ 32)\ \cup\ (41;\ \infty)$

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Answer:

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Step-by-step explanation:

We have been given an expression $q^2+11q$ . We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form $a^2+2ab+b^2$ .

To convert our given expression into perfect square trinomial, we need to add and subtract $(\frac{b}{2})^2$ from our given expression.

We can see that value of b is 11, so we need to add and subtract $(\frac{11}{2})^2$ to our expression as:

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Upon simplifying our expression, we will get:

$(q+\frac{11}{2})^2-\frac{11^2}{2^2}$

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Therefore, our perfect square would be $(q+\frac{11}{2})^2-\frac{121}{4}$ .

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