5/9(F-32) < 0 or 5/9(F-32)>5

1 answer:

3 0

$\dfrac{5}{9}(F-32) \ \textless \ 0\ \ \ |\cdot\dfrac{9}{5}\\\\F-32 \ \textless \ 0\ \ \ |+32\\\\F \ \textless \ 32\\or\\\dfrac{5}{9}(F-32) \ \textgreater \ 5\ \ \ |\cdot\dfrac{9}{5}\\\\F-32 \ \textgreater \ 9\ \ \ |+32\\\\F \ \textgreater \ 41\\\\Answer:\ F \ \textless \ 32\ or\ F \ \textgreater \ 41\ \to\ F\in(-\infty;\ 32)\ \cup\ (41;\ \infty)$

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